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Liula [17]
3 years ago
5

In the winter, a heated home in the Northeast might be maintained at a temperature of 78°F. What is this temperature on the Cels

ius and Kelvin scales? T.r 1.8T.c+32 °C Submit Answer &Next
Chemistry
1 answer:
masya89 [10]3 years ago
6 0

Answer:  25.6^0C,  298.6K

Explanation:

Temperature of the gas is defined as the degree of hotness or coldness of a body. It is expressed in units like ^0C and K  

These units of temperature are inter convertible.

We are given:

Temperature of the gas = 78^0F

Converting this unit of temperature into ^0C by using conversion factor:

^oC=\frac{5}{9}\times (^oF-32)

^0C=\frac{5}{9}\times (78^oF-32)

25.6^0C

Converting this unit of temperature into K by using conversion factor:

K=t^0C+273

K=25.6+273

298.6K

Thus the temperature on the Celsius and Kelvin scales are 25.6^0C  and 298.6K respectively.

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san4es73 [151]

Answer:

an inducer

Explanation:

An Enzyme is a protein molecule found in cells which work as biological catalysts.

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In chemistry inducers are molecules that regulates gene expression, and can bind to protein repressors or activators.

Lactose here acts as an inducer because it inactivates the repressor of an operon.

4 0
3 years ago
BaO2 is a peroxide. Why?
melamori03 [73]

Answer:

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7 0
3 years ago
Read 2 more answers
Calculate the number of moles of Cl2 produced at equilibrium when 3.98 mol of PCl5 is heated at 283.9 deg celsius in a vessel ha
ddd [48]

Answer:

1.274 moles

Explanation:

The equation for the reaction can be represented as follows:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

K = 0.060

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

Concentration of   PCl_5(g)  = \frac{numbers of moles}{volume}

Concentration of   PCl_5(g)  = \frac{3.98}{10.0}

Concentration of   PCl_5(g)  = 0.398 moles

If we construct an ICE table for the above equation; we have:

                       PCl_5(g)           ⇄       PCl_3(g)     +         Cl_2(g)

Initial                0.398                          0                          0

Change            - x                               + x                        + x

Equilibrium    (0.398 - x)                      x                          x

K = \frac{[PCl_3][Cl_2]}{[PCl_5]}

K = \frac{[x][x]}{[0.398-x]}

K = \frac{x^2}{0.398-x}

0.060 = \frac{x^2}{0.398-x}

0.06(0.398-x) = x²

0.02388 - 0.060x = x²

x² + 0.060x - 0.02388 = 0               (quadratic equation)

a = 1;       b= 0.06;      c= -0.02388

Using quadratic formula;

=  \frac{-b+/-\sqrt{b^2-4ac} }{2a}

= \frac{-0.06+/-\sqrt{(0.06)^2-4(1)(-0.02388)} }{(2*1)}

= \frac{-0.060+/-\sqrt{0.0036+0.09552} }{2}

= \frac{-0.06+/-\sqrt{0.09912} }{2}

= \frac{-0.06+/-0.3148}{2}

= \frac{-0.060+0.3148}{2}   or \frac{-0.060-0.3148}{2}

= \frac{0.2548}{2}  or \frac{-0.3748}{2}

= 0.1274 or -0.1874

We go by the positive value which says:

[x] = 0.1274 M

number of moles = 0.1274 × 10.0

= 1.274 moles

∴ the number of moles  of Cl₂ produced at equilibrium = 1.274 moles

7 0
4 years ago
When 15.6 g of fluorite (caf2) reacts with excess sulfuric acid, hydrogen fluoride gas is collected at 709 torr and 25.5°c. sol
lianna [129]
The reaction equation is:

CaF₂ + H₂SO₄ → 2HF + CaSO₄

The molar ratio between fluorite and hydrogen fluoride is 1 : 1.

The moles of fluorite supplied are:

Moles = 15.6 / 78.07
Moles = 0.200

The moles of hydrogen fluoride produced will be 0.2.

Now, we may use the ideal gas equation to determine the temperature:

PV = nRT
T = PV/nR

T = (899 * 7.4) / (0.2 * 62.36)

T = 533.40 K

The temperature will be 260.25 °C
5 0
4 years ago
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poizon [28]
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Potassium Sulfide
Aluminum Oxide
Sodium Oxide
Rubidium Bromide
Calcium Phosphide

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4 0
3 years ago
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