Answer:
15.38 g is the mass for M in the 329 g of sample
Explanation:
Mineral's formula: MS
Our sample weighs 44.9 g
Mass of M: 2.1 g
Our new sample weighs 329 g
We may solve this by a rule of three:
44.9 g of sample contain 2.1 g of M
329 g of sample will contain (329 . 2.1) / 44.9 = 15.38 g
Answer:
10.4 moles
Explanation:
Given parameters:
Number of moles of oxygen = 5.2moles
Number of moles of nitrogen monoxide = ?
Solution:
To solve this problem, we need to work from the known to the unknown specie according to the reaction.
Oxygen gas is known and we can estimate the amount of mole of nitrogen monoxide;
Let us write the balanced reaction equation;
N₂ + O₂ → 2NO
according to this reaction;
1 mole of oxygen gas will produce 2 mole of NO
5.2 moles of oxygen gas will produce (5.2 x 2)moles = 10.4moles
Answer:
Any 4 characteristic of catalyst are:
1. Catalysts remain unchanged at the end of chemical reaction in their mass and structure.
2. They donot start the chemical reaction.
3. They change the rate of the chemical reaction.
4. Catalyst is specific to the chemical reaction. It means that one catalyst can alter the rate of only one chemical reaction.
The balanced chemical reaction is written as:
Sb2S3 + 6HCl = 6SbCl<span>3 + 3H2S
We are given the amount of </span><span>antimony(III) sulfide to be used in the reaction. This is amount will be used for the calculations. We do as follows:
2.85 g Sb2S3 ( 1 mol / </span><span>339.715 g ) ( 6 mol SbCl3 / 1 mol Sb2S3 ) (</span> 228.13 g / mol ) = 11.48 g SbCl3
