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zubka84 [21]
3 years ago
6

What are the letters

Mathematics
2 answers:
marin [14]3 years ago
3 0
E = 7
F = 8
G = 1

First find a number that multiplies by 4 to make a number ending in 2. The options are either 3 or 8.
Try the full multiplication with both 3 and 8 and see which one works. 
Using 3 works up until you try and work out E as E would have to be a two digit number for it to work so therefore the answer to F must be 8. 

Hope this helped.  
maksim [4K]3 years ago
3 0
764x8=6112

Hope this helps :)
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Write the equation of a circle in standard form with center ( -2,4) and radius 6. Show your work.
grigory [225]

Answer:

( x + 2 )² + ( y - 4 )² = 36

Step-by-step explanation:

Standard equation of a circle - ( x - h )² + ( y - k )² = r²

where r = radius and center is at ( h , k )

The given center is ( -2 , 4 )

Thus h = -2 and k = 4

and the given radius is 6

Thus, r = 6

that being said, we plug in the given values into the standard equation

( x - ( - 2 )² + ( y - 4 )² = 6²

Finally we simplify

In - ( -2 ) the two negative signs cancel out and it turns into + 2

6² = 36

The final equation of the circle is ( x + 2 )² + ( y - 4 )² = 36

8 0
2 years ago
The side length of an equilateral triangle is 20 centimeters. Find the length of altitude of the triangle.
gtnhenbr [62]

Answer:

17.3 cm

Step-by-step explanation:

20² = 10² + x²

400 = 100 + x²

300 = x²

x = 17.3 cm

7 0
3 years ago
2x — бу = 12<br> х+ 10 = — 9
Serggg [28]

Answer:

x = -19; y = 25/3

Step-by-step explanation:

Step 1: solve the equation with only one variable

Isolate the variable (x)

x + 10 = -9

x = -9 - 10

x = -19

Step 2: input new information into the other equation

If x = -19, then:

2(-19) - 6y = 12

Isolate the variable (y)

-38 - 6y = 12

-6y = 12 + 38

-6y = 50

y = 50 ÷ 6

y = 50/6

Simplify

y = 25/3

5 0
3 years ago
Find the greatest common factor of 15x 2 y 3 and -20x 3 yz.
vekshin1
Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 
3x^2y. 
7 0
2 years ago
Read 2 more answers
The coordinates of three vertices of square ABCD are A(−212,112),B(−212,−3), and C(2,112).
Lady_Fox [76]

Answer:

<em>P=760</em>

Step-by-step explanation:

Three of the coordinates of the square ABCD are A(-212,112) B(-212,-3) C(2,112). The image below shows the square is not ABCD but ABDC. In fact, this is not a square, as we'll prove later.

Note the x-coordinate of A and B are the same. It means this side is parallel to the y-axis. Also, the y-coordinate of A and C are the same, meaning this side is parallel to the x-axis. The missing point D should have the same x-coordinate as C and y-coordinate as B, i.e. D=(2,-3).

This shape has sides that are parallel to both axes.

To calculate the perimeter we find the length of two sides.

The distance from A to B is the difference between their y-axis:

w=112-(-3)=115

The distance from A to C is the difference between their x-axis:

l=2-(-212)=215

It's evident this is not a square but a rectangle. The perimeter is

P=2w+2l=330+430

P=760

7 0
2 years ago
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