25% or 2/4 and to win one game 50% or 1/2
Answer:
Cost of Amy's Phone= $191.75
Cost of Jill's phone = $191.75*2= $383.5
Step-by-step explanation:
let Amy's phone cost be A
Jill's phone cost = 2A
A/Q-
A +2A = $575.25
3A= $575.25
A=$575.25/3
A= $191.75
then,
Cost of Amy's Phone= $191.75
Cost of Jill's phone= $191.75*2= $383.5
36 two credit courses and 11 three credit courses has been taken.
<u>SOLUTION:
</u>
Given, each course in college X is worth either two or three credits. The members of the men’s swim team are taking a total of 47 courses that are worth a total of 105 credits
.
We have to number of two credit courses and three credit courses are being taken
.
Now, let the number of 2 credits courses be n, then number of 3 credits courses will be
.
And, according to the given information, Total credits = 105
![\begin{array}{l}{\rightarrow \text { Credits for two credit courses }+\text { credits from three credits courses }=105} \\\\ {\rightarrow 2 \times \text { number of two credit courses }+3 \times \text { number of three lcredit courses }=105} \\\\ {\rightarrow 2 \times n+3 \times(47-n)=105} \\\\ {\rightarrow 2 n+141-3 n=105} \\\\ {\rightarrow 3 n-2 n=141-105} \\\\ {\rightarrow n=36}\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bl%7D%7B%5Crightarrow%20%5Ctext%20%7B%20Credits%20for%20two%20credit%20courses%20%7D%2B%5Ctext%20%7B%20credits%20from%20three%20credits%20courses%20%7D%3D105%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%202%20%5Ctimes%20%5Ctext%20%7B%20number%20of%20two%20credit%20courses%20%7D%2B3%20%5Ctimes%20%5Ctext%20%7B%20number%20of%20three%20lcredit%20courses%20%7D%3D105%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%202%20%5Ctimes%20n%2B3%20%5Ctimes%2847-n%29%3D105%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%202%20n%2B141-3%20n%3D105%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%203%20n-2%20n%3D141-105%7D%20%5C%5C%5C%5C%20%7B%5Crightarrow%20n%3D36%7D%5Cend%7Barray%7D)
So, two credits courses count is 36, the three credit courses count is ![47-36 = 11](https://tex.z-dn.net/?f=47-36%20%3D%2011)