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grandymaker [24]
3 years ago
6

How do you solve: 3^x+1=15?

Mathematics
1 answer:
EastWind [94]3 years ago
4 0
It would be 3^x=14 and you just have to find out what number raised to 3 equals 14
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Helppppp please will give brainlist ​
NeX [460]

Answer:

D or answer 4                   y=-5/2x+7

Step-by-step explanation:

Well we can first start of by finding the y-intercept.

Note that when x=0, you can find your y-intercept.

Knowing this, and looking at the table, 7 is the y-intercept because when y=7, x=0.

So we can eliminate choices 'a' and 'c,' or answers 1 and 3, because they have the y-intercept as -7, when it's just 7.

Please know that in the equation:

y = mx + b

y = y-coordinate or any given point

mx = slope

b = y-intercept

Now we must find slope

To find the slope we need to do:

(y2 - y1) / (x2 - x1) or rise/run

The two coordinates I choose to use is (0, 7) and (6, -8).

(-8 - 7) / (6 - 0) = -5/2

-5/2 is the slope

Finally, look for an equation that has 7 as the y-intercept and -5/2 as the slope.

Answer: D or answer 4

7 0
3 years ago
Write two different expressions to represent the sale price of a fishing pole, f, after a 20% discount.
Rom4ik [11]

Answer:

When we have a discount of X% of the original price, the new price is calculated as:

New price = (original price) - (original price)*(X%/100%)

In our case, let's define:

P = original price of the fishing pole

f = price of the fishing pole after the discount

X% = 20%

Then the equation for the price of the fishing pole is:

f = P - P*(20%/100%) = P - P*0.2 = P*(1 - 0.2) = P*0.8

f = 0.8*P

This means that the price after the discount is 0.8 times the original price.

7 0
3 years ago
Find the area of a circle in terms of pi with a radius of 7.4 cm.
Anit [1.1K]
A= \pi  r^{2} =\\A=\pi (7.4)^{2}=\\A=\pi (54.76)=\\A=54.76\pi
4 0
3 years ago
Read 2 more answers
The Quadratic Equation c² + 6c+ 8 = 0<br><br> Show work please
Bad White [126]
The formula for the quadratic formula is x (c in this case) = (-b(+/-)√(b²-4ac))/2a
This is used for an equation in standard quadratic form: ax² + bx + c = 0
1.) Put it in the correct form, if not already in it.
Ex. c² + 6c + 8 = 0
2.) Identify each part of the equation:
a = 1 (the leading coefficient), b = 6 (the coefficient in front of the second variable), c = 8
3.) Plug in each variable answer
c = (-6(+/-)√(6²-4(1)(8))/2(1)
4.) Simplify
c = (-6(+/-)√(36-(4*8))/2
c = (-6(+/-)√(36-32))/2
c = (-6(+/-)√(4))/2
c = (-6(+/-)2)/2
*Here, the equation splits in two. It becomes:
c = (-6+2)/2 AND c = (-6-2)/2
*Simplify again:
c = -4/2 AND c = -8/2
c = -2 AND c = -4
The answers c = -2 and c = -4 would solve the given equation.
Hope this helps! :)
6 0
3 years ago
Read 2 more answers
3x^2-x-16=0 Solve this question
Nadya [2.5K]
X≈2.48207399,<span>−<span>2.14874066</span></span>
4 0
3 years ago
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