The width of a rectangle is 7 meters greater than its length

Mathematics

1 answer:

olga_2 [115]2 years ago

8 0

Answer:

Step-by-step explanation:

The quadratic equation in standard form for the equation that would represent the area of the rectangle is x^2 + 7c - 170 = 0. The area (A) of the rectangle with length, x, and width, y, is: A = x * y. The width of a rectangle is 7 meters greater than its length: y = 7 + l. The area of the rectangle is 170 square meters: A = 170. Substitute A and y in the formula A = x * y. 170 = x * (7 + x). 170 = 7x + x^2. The standard form of the quadratic equation is ax^2 + bx + c = 0. Therefore, 170 = 7x + x^2 in the standard form is: x^2 + 7c - 170 = 0.

You might be interested in

Solve the system of equations by elimination. 2x+8y=10 -4x-9y=-13 x = y =

Reptile [31]

So use cancelation
multiply first equation by 2
2x+8y=10
times 2
4x+16y=20
now add

4x+16y=20
-4x-9y=-13 +
0x+7y=7
7y=7
divide by 7
y=1

subsittue

2x+8y=10
2x+8(1)=10
2x+8=10
subtract 8 from both sides
2x=2
divide by 2
x=1

x=1
y=1

8 0

3 years ago

What is the equation of a line with a slope of -2 and passes through the point 3,5¿

dalvyx [7]

Y - y₁ = m(x - x₁)
y - 5 = -2(x - 3)
y - 5 = -2(x) + 2(3)
y - 5 = -2x + 6
+ 5 + 5
y = -2x + 11

3 0

3 years ago

Simplify this step by step <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-5jk%7D%7B35j%5E2k%5E2%7D%20" id="TexFormula1" tit

VikaD [51]

$\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }$

Remember that:

$\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }$

8 0

2 years ago

Read 2 more answers

How many millimeters are in 58 meters?

MAVERICK [17]

Answer:

58,000

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

a man standing 20m from a tower estimates the angles of elevation of the top and bottom of a flagpole on the tower as 58° and 55

schepotkina [342]

60.56ft

You can get this by creating right triangles with the adjacent side as 20 and using the angles given. You can then find the opposite sides using tangents and then simply add them together.

7 0

2 years ago