Find the measure of arc BC. PLEASE HELP!!

The length of a triangel is three times its with.if the perimiter is at its most 112 centemeters,witch is the greates possible v

iris [78.8K]

I am assuming you do not mean The length of a triangle and you mean The length of a rectangle because the answer you given are the formula for the perimeter of a rectangle. With that said, the answer is D<span>.2w+2*(3w)112

The perimeter of a rectangle can be found by the following equation:

2L + 2W = P
OR
P = 2L + 2W
The equation </span>P = 2L + 2W is read perimeter = 2 times Length + 2 times width

The Question:
<span>The length of a rectangle is three times its width.if the perimeter is at its most 112 centimeters ,which is the greatest possible value of the the width.
</span>
The length of a rectangle
This means the perimeter

is
The word is means to use an equal sign

three times its width
This means 3 times w or 3w
The w = width

perimeter is at its most 112
This means <=
<= means less than or equal to

Ok so lets look at our equation

2L + 2W = P
2w + 2(3w) <= 112

5 0

2 years ago

Last month, when Joe took his puppy to the veterinarian, the puppy weighed 4.8 pounds. This month, the puppy weighed 6.72 pounds

Anvisha [2.4K]

Answer:40% weight increase

Step-by-step explanation:

3 0

2 years ago

What number is in the middle of 25 and 50?

Firdavs [7]

(50-25)/2
25/2
12.5
25+12.5=37.5

6 0

2 years ago

Read 2 more answers

Someone help me please

kvasek [131]

Answer:

(5,1) is the mid point of RS

6 0

2 years ago

Jake has a rectangular garden that measures 12 feet by 14 feet. He wants to increase the area by 50% and plans to increase each

emmasim [6.3K]

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Explanation:</h2><h2 />

First of all, let's calculate the area of the original rectangular garden:

$A=b\times h \\ \\ b:base \\ \\ h:height \\ \\ \\ b=12ft \\ \\ h=14ft \\ \\ \\ A=12(14) \\ \\ A=168ft^2$

Jake wants to increase the area by 50%, so the new area would be:

$A'=168(1.5) \\ \\ A'=252ft^2$

He wants to increase the area by 50% and plans to increase each dimension by equal lengths, x, so this is represented by the figure below, therefore:

$(12+x)(14+x)=252 \\ \\ 168+12x+14x+x^2-252=0 \\ \\ x^2+26x-84=0 \\ \\ \\ Using \ quadratic \ formula: \\ \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ \\ b=26 \\ \\ c=-84 \\ \\ \\ x=\frac{-26 \pm \sqrt{26^2-4(1)(-84)}}{2(1)} \\ \\ x=\frac{-26 \pm \sqrt{1012}}{2} \\ \\ \\ Two \ solutions: \\ \\ x_{1}=-13+\sqrt{253} \approx 2.9\\ \\ x_{2}=-13-\sqrt{253} \approx -28.9 \\ \\ x_{2} \ is \ discarded \ because \ it \ can't \ be \ negatives$

Finally:

<em>In order to increase the area of a rectangular garden that measures 12 feet by 14 feet by 50% Jake must increase each dimension by equal lengths, x:</em>

$x\approx 2.9ft$

<h2>Learn more:</h2>

Dilation: brainly.com/question/10945890

#LearnWithBrainly

6 0

2 years ago