Answer:
$24.875
Step-by-step explanation:
If we use an equation to solve the total amount, like y=9.95x where x is the gallons purchased. We then multiply 9.95 by 2.5 to get 24.875
10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Step-by-step explanation:
Let x be the number of liters of 60% saline solution
Now we require 10 L of 30% saline solution.
Liter soln % liters saline %
30 % 10 0.3
60 % x 0.6
10 % 10-x 0.1
Now forming the algebraic equation,
0.6x + 0.1 (10-x) = 10 (0.3)
0.6x + 1 - 0.1 x = 3
0.5 x = 2
x = 4 ( 4 l of 60 % solution is required. So 10 % saline solution required is 10 - 4 = 6 L).
Hence, 10 L of 30 % saline solution can be formed by mixing 4 L of 60 % saline solution and 6 L of 10 % saline solution.
Answer:
230
Step-by-step explanation:
Answer:
The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.
Step-by-step explanation:
2(5m−4)−3(m−5)2=−3m2+40m−83
Add 3m^2 to both sides.
−3m2+40m−83+3m2=−3m2+40m−83+3m2
40m−83=40m−83
Subtract 40m from both sides.
40m−83−40m=40m−83−40m
−83=−83
−83+83=−83+83
0=0
If you have any questions regarding my answer please tell me in the comments, I will come and answer them. Have a good day.
Answer:
In order to properly answer this, we need to know the measurement of the pool in meters
Step-by-step explanation:
