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Musya8 [376]
3 years ago
14

Martin deposits $200 in a savings account that earns 5% annual interest. four years later, cary deposits $200 in an account earn

ing the same interest. let m represent the balance in martins account and let c represent the amount of money in carys account. choose the pair of expressions that describe the accounts y years after martin opened his account. martin: 200(1.05)y cary: 200(1.05)y+4 martin: 200(1.05)y+4 cary: 200(1.05)y4 martin: 200(0.05)y cary: 200(0.05)y4 martin: 200(1.05)y cary: 200(1.05)y4 choose the equation that relates the balances in the accounts y years after martin opened his account. c = m(1.05)4y m = c(1.05)4y c = 1.22m m = 1.22c
Mathematics
2 answers:
olasank [31]3 years ago
8 0
Both of the answers about Martin and Cary are D
Martin: 200(1.05)y   Cary: 200(1.05)<span>y–4
</span>AND
M<span> = 1.22</span><span>C
</span>
rewona [7]3 years ago
3 0

The formula for the amount of money in an account gaining interest is:

F = P * (1 + i)^n

Where,

F = future value of the money / money with interest

P = present value of money / money invested

i = interest rate

n = number of years

Assuming that y = number of years that Cary has deposited and since Martin has started 4 years ahead therefore n for Martin is y + 4. By establishing that, we get these equations:

<span>Martin, m = 200 * (1.05)^(y + 4)</span>

<span>Cary, c = 200 * (1.05)^y</span>

 

Since Martin’s equation can also be written as:

m = 200 * (1.05)^y * (1.05)^4

Therefore we can relate the equations for Martin and Cary:

m = c * (1.05)^4

<span>m = 1.22 c</span>

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5 0
3 years ago
If the volume of a box is 2x3 + 4x2 − 30xwhich of the dimensions are possible with the given x-value?
Kipish [7]

The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

Step-by-step explanation:

The given is,

                        2 x^{3} + 4 x^{2} -30x................................(1)

Step:1

    Check for option A,

             x = 1, dimensions 8 by 9 by 1  

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(2)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                     = 72............................................(3)

            From equation (2) and (3)

                                -24 ≠ 72

            So, X=1; dimensions 8 by 9 by 1 is not possible.

   Check for option B,

             x = 1, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (1^{3}) + 4 (1^{2} )-30(1)

                                    =2+4-30 = -24...................(4)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30.........................................(5)

            From equation (4) and (5)

                                -24 ≠ 30

            So, X=1; dimensions 2 by 5 by 3 is not possible.

   Check for option C,

            x = 4, dimensions 2 by 5 by 3

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72.............................................(6)

            From the dimensions,

                      Volume = ( 2 × 5 × 3 )

                                     = 30............................................(7)

            From equation (6) and (7)

                               72 ≠ 30

            So, X=4; dimensions 2 by 5 by 3 is not possible.

    Check for option C,

            x = 4, dimensions 8 by 9 by 1

            From the equation (1),

                      Volume = 2 (4^{3}) + 4 (4^{2} )-30(4)

                                    =2(64)+4(16)-30(4)

                                    = 128+64-120

                                    = 72............................................(8)

            From the dimensions,

                      Volume = ( 8 × 9 × 1 )

                                    = 72............................................(9)

            From equation (8) and (9)

                               72 = 72

            So, X=4; dimensions 8 by 9 by 3 is possible.

Result:

           The possible value of x = 4, dimensions 8 by 9 by 1 (option D), if the volume of a box is 2 x^{3} + 4 x^{2} -30x.

         

4 0
3 years ago
Is the open sentence 3z = 2z +5 true or false when z=5?
11111nata11111 [884]
If 3z=2z+5 and z=5, then you’d just plug the 5 in.

3(5)=2(5)+5 —> 15=10+5 —> 15=15

This statement is TRUE because 15 does equal 15.

I hope this helps. :)
8 0
3 years ago
Please can anyone send a question in law of indices I really need it now​
DaniilM [7]

Answer:

I think this is a pretty good question of law of indices

Step-by-step explanation:

Given that

(9^p)(27^q)=3^n\\

a) express n in terms of p and q ,

b) hence if p = 1 and q = 2 find the value of n

Solution to part a)

(9^p)(27^q)=3^n\\\\

Simplify the equation and how do we do that? As we can see that 9 can also be written as 3^2 and 27 can be written as 3^3 we can rewrite the following equation like this,

(3^2)^p(3^3)^q=3^n\\

now we multiply p with 2 and

multiply q with 3 respectively,

(3^{2p})(3^{3q})=3^n\\

now since the bases are same and are multiplying the exponents will add themselves like this, in this equation the number 3 is the base

3^{2p+3q}=3^n\\

now since the bases on the left hand side and on the right hand side are equal the exponents will also be equal so now,

2p+3q=n\\

hence n is expressed in terms of p and q

Solution to part b)

if p = 1 and q = 2 we plug in these values in the above equation we found for n

n = 2p + 3q

n = 2(1) + 3(2)

n = 2 + 6

n = 7

6 0
3 years ago
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