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3 years ago

What is a standard procedure for dividing a 2 digit divisor??? Explain.

Mathematics

1 answer:

strojnjashka [21]3 years ago

6 0

(Daddy Mamma Sissy Bubba Rover=Divide Multiply Subtract Borrow Repeat/remainder)

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Find the value of r in (4, r), (r, 2) so that the slope of the line containing them is −53

Elan Coil [88]

Answer:

C) 7

===========================================

Work Shown:

Use the slope formula

m = (y2-y1)/(x2-x1)

Plug in the given slope we want m = -5/3 and also the coordinates of the points. Then isolate r

m = (y2-y1)/(x2-x1)

-5/3 = (2-r)/(r-4)

-5(r-4) = 3(2-r) .... cross multiplying

-5r+20 = 6-3r

-5r+20+5r = 6-3r+5r .... adding 5 to both sides

20 = 6+2r

20-6 = 6+2r-6 ....subtracting 6 from both sides

14 = 2r

2r = 14

2r/2 = 14/2 .... dividing both sides by 2

r = 7

The slope of the line through (4,7) and (7,2) should be -5/3, let's check that

m = (y2-y1)/(x2-x1)

m = (2-7)/(7-4)

m = -5/3

The answer is confirmed

7 0

3 years ago

Read 2 more answers

Jake has 78 toy cars 49 are red and the rest are green how many cars are green

fredd [130]

Answer:

Step-by-step explanation:

Subtract 78 by 49, you would get 29.

3 0

2 years ago

Read 2 more answers

Ramon makes nectar for a hummingbird feeder by mixing 8 cups of water with 2 cups of sugar. Tiffany makes nectar by mixing 9 cup

cluponka [151]

Answer:

Tiffany

Step-by-step explanation:

Ramon is 4 to 1 water to sugar

Tiffany is 3 to 1 water to sugar

4 0

2 years ago

Solve for x: 4 − (x + 2) −7<br> x −9

olga2289 [7]

Answer:

wjdjdjdn w w. r. fidjsns

8 0

3 years ago

Read 2 more answers

Greta is trying to determine the portion of green candies in various bags of green and yellow candies. Using the information bel

IrinaK [193]

Answer: a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

Step-by-step explanation:

Since we have given that

There are green and yellow candies in each bag.

Bag A: Two thirds of the candies are yellow. What portion of the candies is green?

Part of yellow candies in bag A = $\dfrac{2}{3}$

Part of green candies in bag A would be

$1-\dfrac{2}{3}\\\\=\dfrac{3-2}{3}\\\\=\dfrac{1}{3}$

Bag B: 29 % of the candies are yellow. What portion of the candies is green?

Percentage of candies are yellow = 29%

Portion of candies are green is given by

$1-\dfrac{29}{100}\\\\=1-0.29\\\\=0.71\\\\=\dfrac{71}{100}$

Bag C: 4 out of every 9 candies are yellow. What portion of the candies is green?

Portion of yellow candies = $\dfrac{4}{9}$

Portion of green candies would be

$1-\dfrac{4}{9}\\\\=\dfrac{9-4}{9}\\\\=\dfrac{5}{9}$

Hence, a) $\dfrac{1}{3}$ b) $\dfrac{71}{100}$ c) $\dfrac{5}{9}$

6 0

2 years ago