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krek1111 [17]
3 years ago
6

I need help someone please

Mathematics
1 answer:
IgorLugansk [536]3 years ago
7 0

Answer: The answers are in the steps.

Step-by-step explanation:

A) 4 \frac{1}{2} =  9/2 * 13 =  117/2

B ) 13 ( 58  + 1/2)  

= 754  + 6.5

= 760.5

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Answer:

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Soloha48 [4]

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Step-by-step explanation:

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2root3 sin^<a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail="ac9eec">[email&#160;protected]</a> - <a href
Phantasy [73]

Answer:

Step-by-step explanation:

2\sqrt{3} sin^{2} \alpha -cos\alpha =0\\2\sqrt{3} (1-cos ^2 \alpha )-cos \alpha =0\\2\sqrt{3} -2\sqrt{3} cos^2 \alpha -cos \alpha =0\\2\sqrt{3} cos^2 \alpha +cos \alpha -2\sqrt{3} =0\\cos \alpha =\frac{-1 \pm\sqrt{1^2-4*2\sqrt{3}*(-2\sqrt{3})  } }{2*2\sqrt{3} } \\=\frac{-1 \pm\sqrt{1+48} }{4\sqrt{3} } \\=\frac{-1\pm7}{4\sqrt{3} } \\either~cos \alpha =\frac{6}{4\sqrt{3} }=\frac{\sqrt{3} }{2} \\=cos \frac{\pi }{6} ,cos(2\pi -\frac{\pi }{6} )\\=cos \frac{\pi}{6} ,cos \frac{11\pi }{6}

\alpha =2 n\pi+ \frac{\pi }{6} ,2n\pi +\frac{11\pi }{6} (general~solution)

or~cos\alpha =-\frac{7}{4\sqrt{3} } \\ \alpha =cos^{-1}( \frac{-7}{4\sqrt{3} } )

5 0
3 years ago
10 POINTS!!
7nadin3 [17]

Answer:

D

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We require to calculate the volume (V) of the cone and sphere.

The volume of a cone is calculated as

V = \frac{1}{3}πr²h ( r is the radius and h the height )

Here diameter = 5, hence r = 5 ÷ 2 = 2.5, thus

V = \frac{1}{3}π × 2.5² × 8 ≈ 52.36 cm³

The volume of a sphere is calculated as

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Thus when the ice cream melts it will overflow → D

5 0
4 years ago
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