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faltersainse [42]
3 years ago
9

The vertex form of the equation of a parabola is x= (y-2)^2 + 36, what is the standard form of the equation

Mathematics
1 answer:
frutty [35]3 years ago
4 0

The answer is X= Y^2 - 4y + 40

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-½(x + 1¼) = - 3 + ¼x <br> Solve for x
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Answer:

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x=5.66168710

Step-by-step explanation:

im too lazy. use math-way

6 0
3 years ago
After how many seconds is the height 68 feet? When the equation is h=-16t2+64t+8
Rudiy27
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(2t-5)(2t-3)=0
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5 0
3 years ago
Solve the compound inequality 9 + 3n &gt;= 6 or 5n &lt; 25.
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4 0
3 years ago
Please help me out with this :)
yan [13]

Answer:

y = x - 5

Step-by-step explanation:

Given the equation

y = x + ?

We are being asked what value is added to x to give y

Consider the table, that is

x = 1 → y = - 4

x = 2 → y = - 3

x = 3 → y = - 2

x = 4 → y = - 1

x = 5 → y = 0

x = 6 → y = 1

In each case 5 is being subtracted from x to obtain y, that is

y = x - 5 ← equation relating x and y

6 0
3 years ago
Read 2 more answers
A circle is centered at N(-6, -2). The point E(-1,1) is on the circle.
galina1969 [7]

Answer:

Outside the circle

Step-by-step explanation:

Let's first write the equation of this circle: (x-h)^2+(y-k)^2=r^2, where (h, k) is the center and r is the radius. Here, the center is (-6, -2). We need to find the radius, which will just be the distance from N to E:

NE = \sqrt{(-6-(-1))^2+(-2-1)^2} =\sqrt{25+9} =\sqrt{34}

The radius is √34, which means that r² = 34. So, our equation is:

(x + 6)² + (y + 2)² = 34

Plug in -10 for x and -7 for y:

(x + 6)² + (y + 2)² = 34

x² + 12x + 36 + y² + 4y + 4 = 34

x² + 12x + y² + 4y + 40 = 34

x² + 12x + y² + 4y + 6 = 0

(-10)² + 12 * (-10) + (-7)² + 4 * (-7) + 6 = 7

Since 7 > 0, we know that H lies outside the circle.

6 0
3 years ago
Read 2 more answers
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