All categories

3 years ago

Find the length of the radius of circle C

Mathematics

2 answers:

blondinia [14]3 years ago

5 0

Answer:

Option D. r = 15 units

Step-by-step explanation:

In this question Length of arc is given as s = $\frac{20}{3}\pi$

and angle inscribed at the center is θ = $\frac{4\pi }{9}$

By the formula s = rθ

By placing the values of s and θ we can get the length of radius

$\frac{20\pi }{3}=r(\frac{4\pi }{9} )$

r = $\frac{\frac{20\pi }{3} }{\frac{4\pi }{9} }$

r = $\frac{20\pi }{3}\times \frac{9}{4\pi }$ = 15 unit

Therefore, Option D. r = 15 will be the answer.

Gala2k [10]3 years ago

3 0

Your answer would be C.) because remember always PIE-3.14 and i also did the test

You might be interested in

Robert uses a wheelbarrow to haul wood from the back yard to his neighbor's house located 9 meters away. If he takes two breaks

Naily [24]

Answer:

3 meters

63 meters

Step-by-step explanation:

In order for his two breaks to occur after even distances, simply divide his total path in three:

$B = \frac{9}{3}\\ B=3\ meters$

He will reach his first break after 3 meters.

If he can only take 9 pieces at a time the number of trips required is:

$n=\frac{36}{9}\\ n=4$

Note that he will have to back to the back yard for the first three trips (traveling back the 9 meters path). The total distance traveled is:

$d= 3*(9+9)+9\\d=63\ meters$

He will travel 63 meters.

6 0

3 years ago

Dawn has 5\6 yard of lace. She uses 4\5 of it on a dress and the rest on a jewel box. How much does she use on the jewel box

mr_godi [17]

Answer:

Jewelry box: 1/6 yard

Step-by-step explanation:

4/5 (not 4\5) of her 5/6 yard goes into a dress: (4/5)(5/6 yd) = 2/3 yard.

This is the same as 4/6 yard. The amount of lace remaining, to be used on a jewelry box, is 5/6 - 4/6, or 1/6 yard.

3 0

3 years ago

The formula to find the period of orbit of a satellite around a planet is T^2=(4pi^2/GM)r^3 where r is the orbit's mean radius,

Natalija [7]

The answer is $r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

$T^{2} = \frac{4 \pi^{2}}{GM} r^{3}$

Move $\frac{4 \pi^{2} }{GM}$ to the other side of the equation:
$T^{2} /\frac{4 \pi^{2} }{GM} = r^{3} \\ 
T^{2} *\frac{GM}{4 \pi^{2} } = r^{3}$

Rearrange:
$r^{3} = T^{2} *\frac{GM}{4 \pi^{2} } \\ 
r^{3}= \frac{T^{2} *GM}{4 \pi^{2} } \\ 
r^{3}= \frac{GMT^{2}}{4 \pi^{2} } \\ 
r^{3} = GMT^{2}/4 \pi^{2}$

Since $x^{3}= \sqrt[3]{x}$ , then
$r^{3} = GMT^{2}/4 \pi^{2} \\ 
r= \sqrt[3]{GMT^{2}/4 \pi^{2}}$

3 0

3 years ago

Read 2 more answers

Find (f•g) (x) for the following functions.

Natasha2012 [34]

Answer:

Step-by-step explanation:

f(x) * g(x)= (3x^2-4x-5)(11x-3)

33x^3-44x^2-55x-9x^2+12x+15

33x^3-53x^2-43x+15

6 0

2 years ago

Mark decompose 5/6 into three fractions none of them has a denominator of 6 what fractions did mark use

Sliva [168]

Answer:

2/3 + 2/3 + 1/3.

Step-by-step explanation:

You can use equivalent fractions. 6 is 2x more than <u>3</u>. You can use three as the denominator.

5 0

2 years ago