Answer:
happy birthday
Step-by-step explanation:
thank you
Most people use the decomposition method but i dont know how to do that so i use the Joes method a method similar to decomp. but easier.
canadian way
Find gcf: None
complet trinomial: 18n^2+57-10
find the product=10(18)
=-180
find the sum =57
-3 and 60 goes into both meaning if you multiply 3 and60 you get -180 and if you add them you get 57.
so (n-3)(n+60)
divide by a in this case it 18
so (n<u>-3</u>)(n+<u>60</u>)
18 18
do not divide. treat it like a fraction so you reduce it to lowest terms
(n<u>-3</u>)(n<u>-3)
</u> 18 10
<u /> at this point its reduced to lowest terms so now you take the deniminator and move it beside the "n"
=(18n-3)(10n-3)
therefore your answer is (18n-3)(10n-3)
I hoped this helped :)
<span>45(v−7)=2
45v - 315 = 2
45v = 317
v = 317/45
v = 7 2/45 (7 and 2/45)</span>
Answer:
110.526316
Step-by-step explanation:
hope it helps
The answer is letter c. x2-8x+24-[72/(x+3)]. If you do not know how to solve this using the long division method, you can always evaluate the options through the process of elimination first. Since the degree of the other factor is already 1 (x to the power of 1), you know that option d. is not the correct answer because you know that the other factor must be raised to the power of 2. That leaves us with a, b and c. Working backwards and multiplying the given factor (x+3) with the factor in b, gives us x3-5x2+72. So from there, you know that you have to eliminate 72, which can be removed when it is subtracted by itself. Letter c does just that. Try multiplying (x+3) and option c for yourself :).