Answer:
201
Step-by-step explanation:
The computation is shown below:
Given that

= 52 × 4 - 7
= 208 - 7
= 201
Here we assume that V denotes the square so according to this we solve the given situation
After solving this, the answer is 201
Answer: m1 = 4
m2 = 5
m3 = 2
Step-by-step explanation:
given (21/11, 6/11) = m1 (-1/3) + m2 (3, -2) + m3 (5, 2)
= (-m1 + 3m2 + 5m3) / 11 = 21/11
= (3m1 + (-2)m2 + 2m3) / 11 = 6/11
so that m1 + m2 +m3 = 11
-m1 + 3m2 + 5m3 = 21
3m1 - 2m2 + 2m3 = 6
from this, we get the augmented matrix as
\left[\begin{array}{cccc}-1&1&1&11\\-1&3&5&21\\3&-2&2&6\end{array}\right]
= \left[\begin{array{cccc}-1&1&1&11\\0&4&6&32\\0&-5&-1&-27\end{array}\right] \left \{ {{R2=R2 + R1} \atop {R3=R3 -3R1 }]} \right.
= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&-5&-1&-27\end{array}\right]
= \left[\begin{array}{cccc}-1&1&1&11\\0&1&3/2&8\\0&0&13/2&13\end{array}\right]
(R3 = R3 + 5R2)
this gives m1 + m2 + m3 = 11
m2 + 3/2 m3 = 8
13/2 m3 = 8
13/2 m3 = 13
m3 = 2
m2 = 8 -3/2 (2) = 5
= m1 = 11- 5 - 2 = 4
this gives
m1 = 4
m2 = 5
m3 = 2
I hope this picture helps you!
The correct answer for the question that is being presented above is this one: "<span>The missing digit is 3."</span>
The missing digit is represented by A ⇒ $1A2, where A represents a whole number from 0 to 9.
Try substituting any number from 0 to 9 for A (the middle digit or tens place) , then divide by 11 members.
<span>Option 2: A = 3 ⇒ $1 </span><span>3 </span>2
$ 132 ÷ 11 = $12
The only one-digit that gives a whole number quotient when it takes the place of tens digit in $1 __2 is<span> 3.</span><span> Because $ 132 ÷ 11 = $ 12. (Option 2)</span>
The missing digit is 3.
I think it’s 35w because you distribute: 24w+11w ) and then you add.