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3 years ago

HELP DUE IN 10 MINUTES!! WILL GIVE BRAINLEST!!

Mathematics

1 answer:

Alekssandra [29.7K]3 years ago

3 0

I have attached a photo with solution:

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Find the area of a circle whose circumference is 31.4 centimeters. approximate as 3.14

hoa [83]

To find the circumference of a circle you multiply pi (3.14) by the diameter ad to find the area you multiply pi (3.14) times the radius squared

Since the circumference is 31.4 divide that by pi to find the diameter which is 10

The radius of a circle is half of the diameter, so for this circle the radius is 10 / 2 = 5

Take the radius and square it : 5^2 = 25

Then multiply the squared radius by pi (3.14) to find the are : 25 * 3.14 = 78.5

So the area of this circle is 78.5 centimeters squared

Hope this helps! Mark as Brainliest please! :)))

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3 years ago

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What number is 13% of 52

MaRussiya [10]

$13 \% \ of \ 52= \frac{13}{100}*52= 13*0.52= \boxed{6.76}$

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3 years ago

What is a sequence ?

aksik [14]

Answer:

A particular order in which related events, movements, or things follow each other.

Step-by-step explanation:

Hope this helps have a great day :)

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3 years ago

What are the two square roots of 9/4?

Citrus2011 [14]

Answer:

3/2

Step-by-step explanation:

3^2=9

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A recent study of 500 American males aged 18-21 found that 237 had 1 ticket in the past year, 112 had 2 tickets in the past year

Jobisdone [24]

Answer:

<em>The expected number of tickets is 1.273</em>

Step-by-step explanation:

<u>Expected Value of a Discrete Probability Distribution</u>

Given a discrete distribution with values

x={x1,x2,x3,...,xn}

And respective probabilities

p={p1,p2,p3,...pn}

The expected value EX of the entire distribution is

$EX=\sum_{i}x_i.p_i$

The recent study of American males provides an approximate distribution of probabilities based on the number of tickets they had past year, according to the following data:

237 had 1 ticket

112 had 2 tickets

17 had 3 tickets

5 had 4 tickets

1 had 5 tickets

The total number of tickets is 237+112+17+5+1=372

Taking the number of tickets as the independent variable, then

x={1,2,3,4,5}

Each probability can be found as the relative frequency of the number of tickets as follows:

$\displaystyle p_1=\frac{237}{372}=0.637$

$\displaystyle p_2=\frac{112}{372}=0.301$

$\displaystyle p_1=\frac{17}{372}=0.046$

$\displaystyle p_1=\frac{5}{372}=0.013$

$\displaystyle p_1=\frac{1}{372}=0.003$

Therefore

p={0.637,0.301,0.046,0.013,0.003}

Compute EX

$EX=1*0.637+2*0.301+3*0.046+4*0.013+5*0.003$

$\boxed{EX=1.273}$

The expected number of tickets is 1.273

8 0

3 years ago