Answer:
Wednesday (9 weeks later) = 10th October.
Step-by-step explanation:
We label the days with the initials of the names.
M= 4
D = 7
B = 6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it would be 84 days after this event.
18+ 84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th October
We can check 84 days = 9 weeks
13 days in July makes 31st july
31 days in Aug makes 31st Aug
30 days in Sept makes 30th Sept
= 74 days + 10 days = 84
10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.
Answer:
11 people will get both the prizes.
Step-by-step explanation:
In this question we need to find common integral multiples of 5 and 7 under 400. As you can see in the figure 35th person is the first one to get both ipod and psp. The LCM (least common multiple) of 5 and 7 which is 35 (!!! <em>I hope you know how to LCM of two integers </em>).
Therefore the integral multiples of 35 will be same as the common multiples of 5 and 7. So, figuring out the number of integral multiples of 35 under 400 will give the answer.
To do that divide the number 400 with 35. On performing the division the quotient will be 11 and the remainder will be 15.
Therefore 11 persons out of 400 will get both the prizes.
Similarly if you want to find the number of person getting ipod then divide 400 with 5. The quotient will be 80. ∴ 80 people will get ipod.
And for psp, divide 400 with 7. The quotient will be 57. ∴ 57 people will get psp.
In these divisions, consider just the quotient, here remainder is of no use.
Answer:
9 years old.
Step-by-step explanation:
Since the ages of all of these students are being represented in relation to the middle student's age then we can create formulas for each student and then apply them to the formula for the sum of their ages and solve for the middle child's age (M) like so... (oldest child's age is represented by variable O and youngest child's age is represented by variable Y)
O = M + 6
Y = M - 3
30 = (M+6) + M + (M-3) ... combine like terms
30 = 3M + 3 ... subtract 3 from both sides
27 = 3M ... divide both sides by 3
9 = M
Now we know that the middle child is 9 years old.
Answer: -1 
c < 3
Step-by-step explanation:
Answer:
to be fair this looks hard but i can do just give me five mins
Step-by-step explanation:
