Find the slope of the line passing through the points (−3,−8) and (5,6)
2 answers:
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The equation of the circle with center at (2,-4) and tangent to the line x = -2 is given by:
(2) (x - 2)² + (y + 4)² = 16
<h3>What is the equation of a circle?</h3>The equation of a circle of center and radius r is given by:
The circle has center at (2,-4), hence .
The center is tangent to the line x = -2, hence it has a point at x = -2, since |-2 - 2| = 4, r = 4 -> r² = 16.
Hence the equation of the circle is given by:
(2) (x - 2)² + (y + 4)² = 16
More can be learned about the equation of a circle at brainly.com/question/24307696
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As the name suggests, the slope-intercept form requires you to find the slope and the intercept. Slope-intercept form is y=mx+b
You can find slope by rise over run, or get two points and plug them into the following formula:
. However, if you see that x values increase by one, you can just find the difference between two y values. In this case, the difference is +5 each time, therefore, the slope or <em>m </em>is 5
The intercept is where x=0. Since we know that (1,2) is a point, we subtract 5 from 2 to get the intercept. Therefore, the intercept is -3
Therefore, the formula is y=5x-3
You can find slope by rise over run, or get two points and plug them into the following formula:
The intercept is where x=0. Since we know that (1,2) is a point, we subtract 5 from 2 to get the intercept. Therefore, the intercept is -3
Therefore, the formula is y=5x-3