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vladimir1956 [14]
3 years ago
10

Find the slope of the line passing through the points (−3,−8) and (5,6)

Mathematics
2 answers:
Mrac [35]3 years ago
7 0
The line passing through it is y=7/4x-11/<span>4</span>
Liula [17]3 years ago
3 0
For this you can use the formula of slope: y2-y1/x2-x1

x1 is -3, y1 is -8, x2 is 5, y2 is 6

6- -8 ( two negatives become positive)
6+8=14

5- -3 ( same as before)
5+3=8

so the slope is 14/8

please vote my answer branliest! Thanks.
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AABC is dilated by a factor of 2 to produce AA'B'C!
lakkis [162]

Answer:

D

Step-by-step explanation:

in this case, because it is being dilated by a factor of 2 this means that figure A´B´C´ will be double the size of its pre-image ABC.

each side will now be its double which means:

side A´C´= 10

side B´C´= 6

and side A´B´= 8

since the figure is only increasing its sides the angles of the right triangle remain the same.

<A= 37 degrees

6 0
3 years ago
Read 2 more answers
The breaking strengths of cables produced by a certain manufacturer have a mean, , of pounds, and a standard deviation of pounds
olchik [2.2K]

The question is incomplete. The complete question is :

The breaking strengths of cables produced by a certain manufacturer have a mean of 1900 pounds, and a standard deviation of 65 pounds. It is claimed that an improvement in the manufacturing process has increased the mean breaking strength. To evaluate this claim, 150 newly manufactured cables are randomly chosen and tested, and their mean breaking strength is found to be 1902 pounds. Assume that the population is normally distributed. Can we support, at the 0.01 level of significance, the claim that the mean breaking strength has increased?

Solution :

Given data :

Mean, μ = 1900

Standard deviation, σ = 65

Sample size, n = 150

Sample mean, $\overline x$ = 1902

Level of significance = 0.01

The hypothesis are :

$H_0 : \mu = 1900$

$H_1 : \mu > 1900$

Test statics :

We use the z test as the sample size is large and we know the population standard deviation.

$z=\frac{\overline x - \mu}{\sigma / \sqrt{n}}$

$z=\frac{1902-1900}{65 / \sqrt{150}}$

$z=\frac{2}{5.30723}$

$z=0.38$

Finding the p-value:

P-value = P(Z > z)

             = P(Z > 0.38)

             = 1 - P(Z < 0.38)

From the z table. we get

P(Z < 0.38) = 0.6480

Therefore,

P-value = 1 - P(Z < 0.38)

            = 1 - 0.6480

             = 0.3520

Decision :

If the p value is less than 0.01, then we reject the H_0, otherwise we fail to reject  H_0.

Since the value of p = 0.3520 > 0.01, the level of significance, then we fail to reject  H_0.

Conclusion :

At a significance level of 0.01, we have no sufficient evidence to support that the mean breaking strength has increased.

4 0
3 years ago
What is 2(3a+2b-7) equivalent too?
zloy xaker [14]

Answer:

6a+4b-14

Step-by-step explanation:

For this, we have to use the distributive property.

This means we multiply each value in the parentheses by 2.

2*3a=6a

2*2b=4b

2*(-7)=-14

So our equation is:

6a+4b-14

8 0
3 years ago
Divide. Write your answer in lowest terms. 3/4 divided by 6/1
Trava [24]
Since dividing fractions are not possible, you must first find the reciprocal of 6/1 which is 1/6. And the equation would be written as 3/4*1/6. Cross cancel the 3 and 6 leaving 1/4*1/2=1/8. Thus, your answer is lowest terms is, 1/8.
8 0
3 years ago
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grandymaker [24]

Answer:

<h2><em>4</em><em>1</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>a</em><em>=</em><em>1</em><em>4</em>

<em>b</em><em>=</em><em>2</em><em>9</em>

<em>c</em><em>=</em><em>1</em>

<em>D=</em><em>1</em>

<em>Now</em><em>,</em>

<em>a + b - c - d \\  = 14 + 29 - 1 - 1 \\  = 43 - 1 - 1 \\  =42 - 1 \\  = 41</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
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