What is the slope of a line perpendicular to the line whose equation is 5x+6y=425x+6y=42. Fully reduce your answer.
1 answer:
You might be interested in
Answer:
4 meters
Step-by-step explanation:
Given a quadratic equation in which the coefficient of is negative, the parabola opens up and has a maximum point. This maximum point occurs at the line of symmetry.
Since the divers height, y is modeled by the equation
Step 1: Determine the equation of symmetry
In the equation above, a=-1, b=2, c=3
Equation of symmetry,
Step 2: Find the value of y at the point of symmetry
That is, we substitute x obtained above into the y and solve.
The maximum height of the diver is therefore 4 meters.
Answer:
Where 0 < x < 3
The location of the local minimum, is (2, 0)
The location of the local maximum is at (0, 16)
Step-by-step explanation:
The given function is f(x) = (x + 2)⁴
The range of the minimum = 0 < x < 3
At a local minimum/maximum values, we have;
∴ (-x + 2)³ = 0
x = 2
When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2
We have, f(2) = (-2 + 2)⁴ = 0
The location of the local minimum, is (2, 0)
Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3
When x = 0, -x + 2 = 0 + 2 = 2
Similarly, we have;
-x + 2 = 1, when x = 1
-x + 2 = 0, when x = 2
-x + 2 = -1, when x = 3
Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16
The location of the local maximum is at (0, 16).