Answer:
4 cm ×12 cm
Step-by-step explanation:
To find the dimensions of the sticker, start by forming 2 equations for its area and perimeter.
Perimeter of rectangle= 2(length +breadth)
Let the length and breadth of the rectangle be L and B cm respectively.
2(L +B)= 32
Divide both sides by 2:
L +B= 16 -----(1)
Area of rectangle= length ×breadth
LB= 48 -----(2)
From (1): L= 16 -B -----(3)
Substitute (3) into (2):
(16 -B)(B)= 48
Expand:
16B -B²= 48
B² -16B +48= 0
(B -4)(B -12)= 0
B -4= 0 or B -12= 0
B= 4 or B= 12
Substitute into (3):
L= 16 -4 or L= 16 -12
L= 12 or L= 4
Thus, the dimensions of the sticker is 4 cm ×12 cm.
Answer:

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1. 3/10
2. 1/10
3. -10/3
4. -10
Let
x---------> the length of the rectangle
y--------> the width of the rectangle
we know that
A=84 ft²
[area of rectangle]=x*y-----> 84=x*y-----> equation 1
x=y-5------> equation 2
substitute 2 in 1
84=[y-5]*y-----> 84=y²-5y---------> y²-5y-84=0
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
y=12
x=y-5-----> x=12-5-----> x=7
the answer isthe length of the rectangle is 7 ftthe width of the rectangle is 12 ft