Sample space = {p, r, o, b, a, b, i, l, I, t, y} = 11 possible outcomes
1sr event: drawing an I ( there are 2 I); P(1st I) = 2/11
2nd event drawing also an i: This is a conditional probability, since one I has already been selected the remaining number of I is now 1, but also the sample space from previously 11 outcome has now 10 outcomes (one letter selected and not replaced)
2nd event : P(also one I) = 1/10
P(selecting one I AND another I) is 2/11 x 1/10
P(selecting one I AND another I) =2/110 = 0.018
It is a trick question 13+13 DOES equal 26
(85/86)*688 cg = 680 cg . . . inert ingredient
.. 688 cg -680 cg = 8 cg . . . .active ingredient
Answer:
your answers are
m=2.5003
and
x=2.5009
Step-by-step explanation:
hope this is what you are looking for
have a nice day ^_^