Suppose f(x)=x^3. Find the graph of f(2/3x)
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<h3>Answer: 
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How to get this answer:
Use the unit circle to note that when
(aka 45 degrees)
Beyond this point, cosine is smaller than sine. This means that anything from 0 to pi/4 will have sine be smaller than cosine. It might help to graph y = sin(x) and y = cos(x) on the interval from x = 0 to x = pi.
The two curves y = sin(x) and y = cos(x) intersect at the point
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Here's a more detailed picture of whats going on.
Intersect the intervals and
and you'll end up with the final answer