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4 years ago

What is the appropriate metric unit for measuring the capacity of a water cooler?

Mathematics

2 answers:

Montano1993 [528]4 years ago

8 0

Liters is the best way

vodomira [7]4 years ago

7 0

The best way to measure a volume of this size in Liters. This is a metric unit. There are 1000 liters in one cubic meter.

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Arianna has $0.70 worth of nickels and dimes. She has 4 more dimes than nickels. By

jekas [21]

Answer:

x=2 and y=6

Step-by-step explanation:

thee isn't any other way im sorry but there isn't here is a list:

1 nickel = $0.05 and 5 dimes =$0.50 = $0.55

2 nickels = $0.10 and 6 dimes = $0.60 = $0.70

3 nickels = $0.15 and 7 dimes = $0.75 = $0.85

4 nickels = $0.20 and 8 dimes = $0.80 = $1.00

5 nickels equal $0.25 and 9 dimes equals $0.90 = $1.15

so as you can see the more you add the higher the number gets and if its any lower it won't be enough sorry if you really needed that last part

4 0

3 years ago

Roman buys seed packets for the school garden. One packet of radish seeds costs $1.75. One packet of tomato seeds costs $2.50. L

HACTEHA [7]

Answer:

C. $t=23,r=9$ .

Step-by-step explanation:

Let r represent the cost of one packet of radish seeds and let t represent the cost of one packet of tomato seeds.

Roman spent $62.75

This implies that,

$1.75r+2.5t=62.75...eqn1$

Roman bought 32 packets of seeds and one packet of radish seeds costs
$ 1.75.
One packet of tomato seeds costs $ 2.50.

This implies that,

$r+t=32...eqn2$

Using guess and check means we substitute into the given equation.

A) We substitute $t=8,r=24$ into both equations.

$1.75(8)+2.5(24)=62.75...eqn1$

$14+60\ne 62.75...eqn1$

$8+24=32...eqn2$

Both equations are not satisfied.

B)

We substitute $t=9,r=23$ into both equations.

$1.75(9)+2.5(23)=62.75...eqn1$

$15.75+57.5\ne 62.75...eqn1$

$9+23=32...eqn2$

Both equations are not satisfied.

C)

We substitute $t=23,r=9$ into both equations.

$1.75(23)+2.5(9)=62.75...eqn1$

$40.25+22.5 =62.75...eqn1$

$23+9=32...eqn2$

Both equations are satisfied.

Hence the solution is,

$t=23,r=9$

D) We substitute $t=24,r=8$ into both equations.

$1.75(24)+2.5(8)=62.75...eqn1$

$42+20\ne 62.75...eqn1$

$24+8=32...eqn2$

Both equations are not satisfied.

4 0

4 years ago

Read 2 more answers

Hi!

WARRIOR [948]

D

Radius of the circle is the length of rectangle divided by 2 (7cm)

Area of circle: pi*r²
Pi= 22/7

(22/7)*7²
=154

Since its a half circle, divide 154 by 2 =77

Area of rectangle:14*9=126

Subtract the circle from the rectangle: 126-77=49

3 0

3 years ago

An Elevator descends into a mine shaft at the rate of 5m/min. If the descend starts from 15m above the ground, how long will it

zhenek [66]

First of all, assuming that the "ground level" is 0;

The lift is not starting from 0, so we also need to account for the extra 15 meters above the ground the lift is.

The total distance the lift would cover in the downward direction: 15+350=365m

Now, you know that the lift covers 5 m/min

Therefore, 5x=365 (ignoring units because they can complicate things)

x=365/5
x=73 minutes

Therefore, they would take 73 minutes to reach 350 m deep into the ground with a starting position 15 m above the ground.

Hope I helped :)

5 0

3 years ago

According to Nielsen Media Research. of all the U.S. households that owned at least one television set, 83% had two or more sets

Rudik [331]

Answer:

The proportion of U.S. households that owned two or more televisions is 83%.

Step-by-step explanation:

To determine whether the proportions of U.S. households that owned two or more televisions is less than 83% or not let us perform a hypothesis test for single proportion.

Assumptions:

The sample size (n) selected by the local cable company is 300 which is quite large. Then according to the Central limit theorem the sampling distribution of sample proportion follows a normal distribution with mean p and standard deviation $\sqrt{\frac{p(1-p)}{n} }$ .

Since the sampling distribution of sample proportions follows a normal distribution use the z-test for one proportion to perform the test.

The hypothesis is:

$H_{0}$ : The proportion of U.S. households that owned two or more televisions is 83%, i.e. $p=0.83$

$H_{1}$ :The proportion of U.S. households that owned two or more televisions is less than 83%, i.e. $p< 0.83$

Decision Rule:

At the level of significance α = 0.05 the critical region for a one-tailed z-test is:

$\\ Z\leq -1.645\\$

**Use the z table for the critical values.

So, if $\\ Z\leq -1.645\\$ the null hypothesis will be rejected.

Test statistic value:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}$

Here $\hat{p}$ is the sample proportion.

Compute the value of $\hat{p}$ as follows:

$\hat{p}=\frac{X}{n} \\=\frac{240}{300}\\ =0.80$

Now compute the value of the test statistic as follows:

$z=\frac{\hat{p}-p}{\sqrt{\frac{p(1-p)}{n}}}\\=\frac{0.80-0.83}{\sqrt{\frac{0.83*(1-0.83)}{300} } } \\=-1.383$

The test statistic is -1.383 which is more than -1.645.

Thus, the test statistic lies in the acceptance region.

Hence we fail to reject the null hypothesis.

Conclusion:

At 0.05 level of significance we fail to reject the null hypothesis stating that the proportion of U.S. households that owned two or more televisions is 83%.

6 0

3 years ago