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solmaris [256]
3 years ago
10

Please can somebody help me with this question please...!

Mathematics
1 answer:
olga55 [171]3 years ago
4 0
Since you are given that the student registered early, the total number you deal with is all students who registered early.

211 + 329 = 540

number of undergraduates who registered early = 211

Among students who registered early:

p(undergraduate) = 211/540
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Identify the 33rd term of the arithmetic sequence 9, 7 and one half, 6...
marta [7]

Answer:

  -39

Step-by-step explanation:

The general term of an arithmetic sequence is ...

  an = a1 +d(n -1)

This sequence has first term a1=9 and common difference d=(7.5-9) = -1.5. Then the 33rd term is ...

  a33 = 9 -1.5(33 -1) = 9 -48 = -39

The 33rd term is -39.

5 0
3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
3 years ago
Read 2 more answers
What is 20 / 65.9635
anastassius [24]

Answer:

the answer to your question is 0.3031979807

4 0
3 years ago
Read 2 more answers
tickets to a play cost 5 dollars for adults and 2 dollars for children. if 1750 tickets were sold for a total of 7100 dollars, h
Sever21 [200]
Let x = number of adults tickets sold
then, 1750 - x = number of children tickets sold

We know that the cost for adult tickets is $5 and and children is above calculated so sum total tickets sold cost is $7100.

($5)(x) + ($2)(1750-x) = $7100
5x - 2x + 3500 = 7100
3x = 3600
x = 1200

8 0
3 years ago
Solve the system of equations <br> 3x-4y=18<br> -2x-3y=5
oksian1 [2.3K]
\left\{\begin{array}{ccc}3x-4y=18&/\cdot2\\-2x-3y=5&/\cdot3\end{array}\right\\\\+\left\{\begin{array}{ccc}6x-8y=36\\-6x-9y=15\end{array}\right\\-------------\\.\ \ \ \ \ \ \ -17y=51\ \ \ \ |:(-17)\\.\ \ \ \ \ \ \ \ \ y=-3\\\\3x-4(-3)=18\\3x+12=18\\3x=18-12\\3x=6\ \ \ \ |:3\\x=2\\\\Answer:x=2\ and\ y=-3\to(2;-3)

6 0
3 years ago
Read 2 more answers
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