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Zarrin [17]
3 years ago
10

Jefferey Says he has 6.8 dollars. How to you write the decimal 6.8 when it refers to money? Explain.

Mathematics
2 answers:
Bogdan [553]3 years ago
8 0
6 Dollars and 80 cents
viktelen [127]3 years ago
7 0
Okay well if he has 6.8 dollars that would be in decimal format.  However, this is actually $6.80.  That is six dollars and 80 cents.

Lets say you had $6 and 75 cents.  You can write that as 6.75 as well since the conversion factor for 1 dollar is 100 pennies.
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Please help Thank you in advance
Law Incorporation [45]
The answer is 3x^2
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5 0
3 years ago
Which number is an integer?<br><br> -3/4 1/5 2 42/3
Reika [66]

The Answer:

2 is an integer.

3 0
3 years ago
What is the equation of the oblique asymptote?<br> h(x) = x² – 3x - 4/x + 2
NNADVOKAT [17]

Simplifying h(x) gives

h(x) = (x² - 3x - 4) / (x + 2)

h(x) = ((x² + 4x + 4) - 4x - 4 - 3x - 4) / (x + 2)

h(x) = ((x + 2)² - 7x - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 14 - 8) / (x + 2)

h(x) = ((x + 2)² - 7 (x + 2) - 22) / (x + 2)

h(x) = (x + 2) - 7 - 22/(x + 2)

h(x) = x - 5 - 22/(x + 2)

An oblique asymptote of h(x) is a linear function p(x) = ax + b such that

\displaystyle \lim_{x\to\pm\infty} h(x) - p(x) = 0

In the simplified form of h(x), taking the limit as x gets arbitrarily large, we obviously have -22/(x + 2) converging to 0, while x - 5 approaches either +∞ or -∞. If we let p(x) = x - 5, however, we do have h(x) - p(x) approaching 0. So the oblique asymptote is the line y = x - 5.

4 0
2 years ago
Provide an appropriate response. the regression line for the given data is = 1.488x + 60.46. determine the residual of a data po
kap26 [50]
Do you have answer choices ?

7 0
3 years ago
Which dilation is shown by this graph?
beks73 [17]

Answer:

1/3

Step-by-step explanation:

Take the far side original length and dilated length 3/9 divide it = 1/3 and that’s the answer

5 0
3 years ago
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