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2 years ago

Jefferey Says he has 6.8 dollars. How to you write the decimal 6.8 when it refers to money? Explain.

Mathematics

2 answers:

Bogdan [553]2 years ago

8 0

6 Dollars and 80 cents

viktelen [127]2 years ago

7 0

Okay well if he has 6.8 dollars that would be in decimal format. However, this is actually $6.80. That is six dollars and 80 cents.

Lets say you had $6 and 75 cents. You can write that as 6.75 as well since the conversion factor for 1 dollar is 100 pennies.

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Graph the image of H(-8,5) after a reflection over the x-axis.<br><br> Answer ?

TEA [102]

Answer: plot a point at (-8, -5)

The y coordinate flips from positive to negative, or vice versa, when we reflect over the horizontal x axis. The x coordinate stays the same.

The rule can be written as $(x,y) \to (x,-y)$

6 0

3 years ago

There are 48 grapes in a bag. Four friends are sharing the grapes.

xeze [42]

48 divided by 4

Step-by-step explanation:each freind gets 12 grapes

5 0

3 years ago

Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a

Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

$y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)$

$y-620=\dfrac{749-620}{70-30}(x-30)$

$y-620=\dfrac{129}{40}(x-30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)$

$y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}$

Adding 620 on both sides, we get

$y=\dfrac{129}{40}x-\dfrac{387}{4}+620$

$y=\dfrac{129}{40}x+\dfrac{2480-387}{4}$

$y=\dfrac{129}{40}x+\dfrac{2093}{4}$

We need to find the y-value for $x=57$ .

$y=\dfrac{129}{40}(57)+\dfrac{2093}{4}$

$y=183.825+523.25$

$y=707.075$

$y\approx 707.1$

Therefore, the required linear equation for the given situation is $y=\dfrac{129}{40}x+\dfrac{2093}{4}$ and the average score for persons taking a 57-hour review course is 707.1.

4 0

2 years ago

allochka39001 [22]

The answer is 90 I think I multiplied 6*3 =18 *4 =72( for every rectangle )then 3*3 =9 for the square (2 squares ) 9*2=18

6 0

2 years ago

11x + 12 = 8x - 9 ... please

Marat540 [252]

Assignment: $\bold{\Solve \ Equation: \ 11x+12=8x-9}$