All categories

1 year ago

Explain how to calculate and find 32% percent of 150. Correct answer gets brainiest

Mathematics

2 answers:

Ray Of Light [21]1 year ago

8 0

Step-by-step explanation:

when finding the percentage of a number, multiply the number by the percentage's decimal form.

here's an example: 20% of 300

20% is 20/100 which is 0.20

now we just multiply

0.20×300=60

now for 32% of 150

32%--->32/100---->0.32

0.32×150=48

there you go! hope that helped

kozerog [31]1 year ago

7 0

Answer:

Step-by-step explanation:

You can easily find the percent of a number by multiplying the percent in decimal format (0.32) by the number you want to find the percent of.

150 * 0.32 = 48

You might be interested in

Estimate the product. Solve using an area model and the standard algorithm. Remember to express your products in standard form.

snow_tiger [21]

Answer:

Step-by-step explanation:

Using the area model and standard algorithm, we have:

332 (tenths)

× 21

332

664

6972 tenths = 697.2

30 + 3 tenths

1 300 32 332

20 600 64 664

33.2 × 21 = 30 × 1 = 30

8 0

2 years ago

Give the equation of a line that has no x-intercepts no y-intercepts an infinite number of y-intercepts a point that is both the

WITCHER [35]

Answer:

The x-intercept is (-2,0)

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

A picture frame can hold a photograph that is 16 inches long and 12 inches wide

antiseptic1488 [7]

I think you do 16*12=196

3 0

2 years ago

Read 2 more answers

The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes

Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(completing the exam in one hour or less)

P(x < 60)

$P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)$

Calculation the value from standard normal z table, we have,

$P(x < 60) =0.023= 2.3\%$

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

$P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%$

c) P(completing the exam in more than 90 minutes)

P(x > 90)

$P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)$

$= 1 - P(z \leq 1)$

Calculation the value from standard normal z table, we have,

$P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%$

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

$\dfrac{15.87}{100}\times 60 = 9.52\approx 10$

Approximately, 10 students of class will require more than 90 minutes to complete the test.

4 0

3 years ago

(Disjoint vs. overlapping events) If you are picking a number between 1-20 what is the probability that you will pick a number g

8090 [49]

9/20

the numbers that would satisfy this are 15,16,17,18,19,20, 1,2,3

so there are 9/20

7 0

3 years ago

Read 2 more answers