Answer:
Center: (-5,10)
Radius: 2
Step-by-step explanation:
The equation of the circle in center-radius form is:

Where the point (h,k) is the center of the circle and "r" is the radius.
Subtract 121 from both sides of the equation:

Add 10x to both sides:

Make two groups for variable "x" and variable "y":

Complete the square:
Add
inside the parentheses of "x".
Add
inside the parentheses of "y".
Add
and
to the right side of the equation.
Then:

Rewriting, you get that the equation of the circle in center-radius form is:

You can observe that the radius of the circle is:

And the center is:

Answer:
2xy - 6x +2y
Step-by-step explanation:
12xy - 10xy = 2xy
5y - 3y = 2y
2xy - 6x + 2y
Answer:
that is a whole lot of simple intrest
Answer:
63rs
explanation:
collect like terms
12*2=24rs
21*2=42rs
then add 24+42=66rs
then subtract 3rs
then just add rs