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3 years ago

What is this question MUST HELP

Mathematics

2 answers:

zlopas [31]3 years ago

5 0

The answer is 8/63 then shade 8 by 63

zvonat [6]3 years ago

3 0

Well, first you make the denominators the same. They both can make 63. So 4/7 times 9 for the numerator and denominator and for 2/9 times 7. So they would be 14/63 for 2/9 and 36/63 for 4/7. Then you multiply the two numerators which would be 504/63, which would be 8.

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Each year three space shuttles are launched, two in June and one in October. If each shuttle is known to occur without a delay i

Veronika [31]

Answer:

0.271 or 27.10%

Step-by-step explanation:

If the present month is January, in 16 months there will be three space shuttles launched (two in June and one in October).

The probability that at least one launch will be delayed is 100% minus the probability that no launch will be delayed:

$P(delay>0) = 1 - P(delay=0)\\P(delay>0) = 1 -0.90^3\\P(delay>0) = 0.271$

The probability that at least one of the launches in the next 16 months will be delayed is 0.271 or 27.10%.

4 0

4 years ago

Type A is 2 feet tall and grows at a rate of 17 inches per year. Type B is 10 feet tall and grows at a rate of 5 inches per year

Svetllana [295]

Answer:

Therefore after 3 years the height of these tree will be same.

Step-by-step explanation:

Given that,

Type A is 2 feet tall and grows at a rate of 17 inches.

Type B is 10 feet tall and is growing at a rate of 5 inches.

1 feet = 12 inches,

2 feet= (12×2) inches = 24 inches

5 feet= (12×5) inches = 60 inches

Let after t years, the height of these tree will be same.

After t years, the height of type A is =(24+17t)

After t years, the height of type B is =(60+5t)

According to the problem,

24+17t=60+5t

⇒17t-5t=60-24

⇒12t = 36

⇒t = $\frac{36}{12}$

⇒t=3

Therefore after 3 years the height of these tree will be same.

7 0

3 years ago

Which statement is true?

adell [148]

Answer:

Answer is the 2nd one.

Step-by-step explanation:

4 0

3 years ago

A radioactive gas with a half-life of 2.4 days accidentally leaks into a room. If the radiation level is now 25% above a safe am

Tatiana [17]

If the radiation level is 100%, it would take 2.4 days to take the radiation level to 50%. However, the situation implies that the radiation level is 25% only, so we need to take 25% from 2.4 days to know the timeframe for a room to be emptied from the radioactive gas. 2.4 days multiplied by 0.25 will give a result of 0.6 day - the timeframe needed to empty the room out of the radioactive gas.

8 0

3 years ago

Koda is solving 13 × 16. He used an area model to help work through each step. Which calculation did Koda make to get the highli

Anastasy [175]

Step-by-step explanation:

Since we have given that

Koda is solving

$13\times 16$