Answer:
A(t) = 676π(t+1)
Correct question:
A rain drop hitting a lake makes a circular ripple. Suppose the radius, in inches, grows as a function of time in minutes according to r(t)=26√(t+1), and answer the following questions. Find a function, A(t), for the area of the ripple as a function of time.
Step-by-step explanation:
The area of a circle is expressed as;
A = πr^2
Where, A = Area
r = radius
From the case above.
The radius of the ripple is a function of time
r = r(t) = 26√(t+1)
So,
A(t) = π[r(t)]^2
Substituting r(t),
A(t) = π(26√(t+1))^2
A(t) = π(676(t+1))
A(t) = 676π(t+1)
Answer: 1.1818^37 kg
Step-by-step explanation:
Given that:
Orbit speed = 1300 km/s
Radius (r) = 18 light days
Mass of object the star is orbiting :
Using the relation :
M = rv² / G
Where ; r = Radius in m ; v = velocity in m/s
G = 6.67 * 10^-11 = gravitational constant
18 light days in meters = 4.662 * 10^14 m
v = 1300km/s to m/s
v = (1300 * 1000)m /s = 1300000 m/s = 1.3 * 10^6 m/s
Hence ;
M = (4.662 * 10^14 * (1.3 * 10^6)^2 / (2/3) * 10^-10
M = (4.662 * 10^14) * (1.69 * 10^12) / (2/3) *10^-10
M = (7.87878 * 10^26) / 6.67 * 10^-11
= 1.1818^37 kg
Answer:
there is no answer for this problem unless you use even numbers.
Step-by-step explanation:
Answer:
Option D (most probably)
Step-by-step explanation:
It definitely won't be C because Rational numbers need not be terminating. A and B are clearly wrong, so its most probably D
Answer:
252 inches since the are 36 inches in a yard
