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saw5 [17]
3 years ago
10

Consider the chemical equation below. Upper M g (upper O upper H) subscript 2 plus 2 upper H upper N upper O subscript 3 right a

rrow upper M g (upper N upper O subscript 3) subscript 2 plus 2 upper H subscript 2 upper O. Which is the net ionic equation? Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O. Upper M g superscript 2 plus, plus 2 upper O upper H superscript minus, plus 2 upper H superscript plus right arrow upper M g superscript 2 plus, plus 2 upper H subscript 2 upper O. Upper M g superscript 2 plus, plus 2 upper N upper O subscript 3 superscript minus right arrow upper M g superscript 2 plus plus 2 upper N upper O subscript 3 superscript minus. Upper M g superscript 2 plus plus 2 upper O upper H superscript minus plus 2 upper H superscript plus plus 2 upper N upper O subscript 3 superscript minus right arrow upper M g superscript 2 plus, plus 2 upper N upper O subscript 3 superscript minus plus 2 upper H subscript 2 upper o.
Chemistry
2 answers:
masha68 [24]3 years ago
8 0

Answer:

Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O.

Explanation:

i just took the test , i hope this helps:)

Mashutka [201]3 years ago
3 0

Answer:

a

Explanation:

I took the test :)

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2 years ago
En un matraz, disponemos de 100 g de gas oxígeno que se encuentran a 1 at de presión y 273 K de temperatura. Calcular : a) el nú
Misha Larkins [42]

Answer:

Explanation:

Dado que:

masa de oxígeno gaseoso = 100 g

presión = 1 atm

temperatura = 273 K

(a)

número de moles de oxígeno contenidos en el matraz = masa de oxígeno / masa molar de oxígeno

= 100 g / 16 gmol⁻¹

= 6.25 moles

(b) El número de moléculas de oxígeno es el siguiente:

Dado que 1 mol de oxígeno gaseoso contiene 6.023 * 10²³ moléculas de oxígeno.

Entonces, 6.25 moles contendrán:

= (6.25 ×  6.023 * 10²³) moléculas de oxígeno.

≅ 3.764 × 10²³ moléculas de oxígeno.

(c) El número de átomos de oxígeno es:

= 2 × 3.764 × 10²³

= 7.528 × 10²³ átomos de oxígeno

(d) Usando la ecuación de gas ideal

PV = nRT

El volumen ocupado por el oxígeno = \dfrac{nRT}{P}

Volumen ocupado por oxígeno = \dfrac{ 6.25 * 8.314 *273}{1}

Volumen ocupado por oxígeno= 14185.76 m³

3 0
3 years ago
When 189.6 g of ethylene (C2H4) burns in oxygen to give carbon dioxide and water, how many grams of CO2 are formed?
Andreyy89

Answer:

6.76 g

Explanation:

3 0
3 years ago
1. For each of the following, convert the word equation into a formula equation, BUT do not balance! (4 pts each = 12 pts)
daser333 [38]

Answer:

  • 1a) BaClO₃(s) → BaCl₂(g) + O₂(g)

  • 1b) Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

  • 1c) Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

  • 2a) Calcium hydroxide and hydrogen gas

  • 2b) Tin(II) silicate and Lead(IV) permanganate

  • 2c) Magnesium oxide and water

  • 2d) No product

  • 2e) Mercury and iodine

  • 2f) Calcium chloride and iodine

  • 2g) Strontium phosphite and cesium nitride

  • 2h) Carbon dioxide, water, and sulfur dioxide

  • 2i) Iron oxide(III) and carbon dioxide

  • 2j) Magnesium acetate and hydrogen gas

  • 2k) Calcium iodide

Explanation:

1. For each of the following, convert the word equation into a formula equation, BUT do not balance!

a) Barium chlorate → Barium chloride + Oxygen

<u>1. Chemical formulas</u>

Barium chlorate:

  • It is a salt: an ionic compound.
  • Barium has oxidation state +2
  • Chlorate is the ion ClO₃⁻
  • Swap the oxidation numbers to write the subscripts: 2 goes to ClO₃ and 1 goes to Ba
  • Chemical formula Ba(ClO₃)₂
  • It is solid: Ba(ClO₃)₂(s)

Barium chloride:

  • It is a salt: an ionic compount
  • Barium has oxidation state +2
  • Chlorine is in oxidation state -1
  • Swap the numbers to write the subscripts: 2 goes to Cl and 1 goes to Ba
  • BaCl₂
  • It is solid BaCl₂(s)

Oxygen:

  • It is a diatomic gas molecule
  • O₂(g)

<u />

<u>2. Write the unbalanced molecular equation:</u>

  • BaClO₃(s) → BaCl₂(s) + O₂(g)

b) Chlorine + Potassium nitride → Nitrogen + Potassium chloride

<u>1. Chemical formulas</u>

Chlorine:

  • It is a diatomic gas molecule
  • Cl₂(g)

Potassum nitride

  • It is a salt
  • Potassium has oxidation state +1
  • Nitrogen is with oxidation state +3
  • Swap the oxidation states
  • K₃N
  • It is solid: K₃N(s)

Nitrogen:

  • It is a diatomic gas
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Potassium chloride

  • It is a salt (ionic compound)
  • Potassium has oxidation state +1
  • Chlorine is in oxidation state -1
  • Swap the oxidation numbers
  • KCl
  • It is solid: KCl(s)

<u>2. Write the unbalanced molecular equation</u>

<u />

  • Cl₂(g) + K₃N(s) → N₂(g) + KCl(s)

c) Sodium nitride + Aluminum bromate → Aluminum nitride + Sodium bromate

<u>1. Chemical formulas</u>

Sodium nitride

  • It is a salt (ionic compound)
  • Sodium has oxidation state +1
  • Nitrogen is with oxidation state -3
  • Swap the oxidation numbers
  • Na₃N
  • It is in aqueous solution
  • Na₃N (aq)

Aluminum bromate

  • Salt
  • Aluminum has oxidation state +3
  • Bromate is the ion BrO₃⁻
  • Swap the oxidation states
  • Al(BrO₃)₃ (aq)

Aluminum nitride

  • Both Al and N have oxidation state 3, which simply
  • AlN(s). It is not soluble in water.

Sodium bromate

  • Na(BrO₃)₃ (aq)

<u>2. Write the unbalanced molecular equation</u>

  • Na₃N(aq) + Al(BrO₃)₃(aq) → AlN(s) + Na(BrO₃)₃(aq)

<h2>This is a long answer with more than 5,000 charaters; thus, I have to add the rest of the explanations on a separate file.</h2><h2></h2><h2>The attached file contains the complete answer.</h2>
Download pdf
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3 years ago
How many valence electrons does the following isotope have?
Helen [10]

Answer:

I have solution to your question

5 0
2 years ago
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