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saw5 [17]
3 years ago
10

Consider the chemical equation below. Upper M g (upper O upper H) subscript 2 plus 2 upper H upper N upper O subscript 3 right a

rrow upper M g (upper N upper O subscript 3) subscript 2 plus 2 upper H subscript 2 upper O. Which is the net ionic equation? Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O. Upper M g superscript 2 plus, plus 2 upper O upper H superscript minus, plus 2 upper H superscript plus right arrow upper M g superscript 2 plus, plus 2 upper H subscript 2 upper O. Upper M g superscript 2 plus, plus 2 upper N upper O subscript 3 superscript minus right arrow upper M g superscript 2 plus plus 2 upper N upper O subscript 3 superscript minus. Upper M g superscript 2 plus plus 2 upper O upper H superscript minus plus 2 upper H superscript plus plus 2 upper N upper O subscript 3 superscript minus right arrow upper M g superscript 2 plus, plus 2 upper N upper O subscript 3 superscript minus plus 2 upper H subscript 2 upper o.
Chemistry
2 answers:
masha68 [24]3 years ago
8 0

Answer:

Upper H superscript plus, plus upper O upper H superscript minus right arrow upper H subscript 2 upper O.

Explanation:

i just took the test , i hope this helps:)

Mashutka [201]3 years ago
3 0

Answer:

a

Explanation:

I took the test :)

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Answer:

w= - 1.7173 kJ, q= 1.7173 kJ, q(rev) = 1717.3 J = 1.7173 kJ.

Explanation:

Okay, from the question we are given the information below;

Number of moles, n= 1 mole; initial volume, v(1) = 1.0 litres (L); pressure (p) = 5atm, final volume(v2) = 2.0 Litres(L) ; the workdone, w= not given; the heat, q and q(rev)= not given and the gas was said to expand isothermally.

So, this question is a question from the part of chemistry known as thermodynamics. Therefore, grip yourself we are delving into thermodynamics 'waters' now.

For expansion isothermally; the workdone, w= -nRT ln v2/v1.

Where T= temperature= 25° C = 298 k and R= gas constant.

Therefore; workdone, w = - 1 × 8.314 × 298 × ln(2/1).

Workdone,w= - 1717.32204643. =

- 1717.3 Joules (J).

==> Workdone,w= - 1.7173 kJ.

Then, we are to find q. q can be solved by using the first law of thermodynamics, which by mathematical representation is:

∆U= q + w. Where ∆U= change in internal enegy. Since the question is dealing with isothermal expansion, there is this rule that says for an isothermal expansion ∆U = 0.

Hence, 0 =q + [- 1717.3 Joules (J)].

q=1717.3 J = 1.7173 kJ.

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q(rev) = 1 × 8.314 × 298 ln (2/1).

q(rev) = 1717.3 J = 1.7173 kJ.

PS: please note the negative signs in the workdone and the positive sign in the q(rev).

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