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tekilochka [14]
2 years ago
15

What is the amount of solute required if the solution is 50 ml and the solvent is 35 ml. Solve and explain

Chemistry
1 answer:
e-lub [12.9K]2 years ago
3 0

Answer:

15 mL of the solute

Explanation:

From the question given above, the following data were obtained:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution is simply defined as:

Solution = solute + solvent

With the above formula, we can easily obtain the solute in the solution as follow:

Solution = 50 mL

Solvent = 35 mL

Solute =?

Solution = solute + solvent.

50 = solute + 35

Collect like terms

50 – 35 = solute

15 = solute

Solute = 15 mL

Therefore, 15 mL of the solute is required.

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Fulgurites are the products of the melting that occurs when lightning strikes the earth. Microscopic examination of a sand fulgu
BlackZzzverrR [31]

Answer:

Fe₃Si₇

Explanation:

In order to determine the empirical formula, we have to follow a series of steps.

Step 1: Determine the percent composition

Fe: 46.01%

Si: 53.99%

Step 2: Divide each percentage by the atomic mass of the element

Fe: 46.01/55.85 = 0.8238

Si: 53.99/28.09 = 1.922

Step 3: Divide all the numbers by the smallest one

Fe: 0.8238/0.8238 = 1

Si: 1.922/0.8238 = 2.33

Step 4: Multiply by numbers that make the coefficients whole.

Fe: 1 × 3 = 3

Si: 2.33 × 3 = 7

The empirical formula is Fe₃Si₇.

5 0
3 years ago
How many milligrams of sodium sulfide are needed to completely react with 25.00 ml of a 0.0100 m aqueous solution of cadmium nit
NARA [144]
Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)

v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol

n(Na₂S)=n{Cd(NO₃)₂}=cv

m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv

m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
5 0
3 years ago
Read 2 more answers
If you measure the mass of a liquid is 11.50 g and its volume as 9.03 ml how many significant figures should its density value h
MAXImum [283]

To get a result with the best degree of precision, the number of significant figures should be equal to the smallest number of significant figures of the given numbers. In this case, the smallest is 3 as given by the number 9.03 mL.

Therefore density is:

<span>11.50 g / 9.03 mL = 1.27 g/mL</span>

3 0
3 years ago
Read 2 more answers
Calculate molality,molarity and mole fraction of KI if the density of 20%(mass) aqueous KI is 1.202 g/mL
Scorpion4ik [409]
Basis: 1 L of the substance.
               (1.202 g/mL) x (1000 mL) = 1202 g 
                   mass solute = (1202 g) x 0.2 = 240.2 g
                   mass solvent = 1202 g x 0.8 =  961.6 g
                   moles KI = (240.2 g) x (1 mole / 166 g)  = 1.45 moles
                   moles water = (961.6 g) x (1 mole / 18 g) = 53.42 moles
1. Molality = moles solute / kg solvent 
                  = 1.45 moles / 0.9616 kg = 1.5 m
2. Molarity = moles solute / L solution
                  = 1.45 moles / 1 L solution = 1.45 M
3. molar mass = mole solute / total moles
                        =  1.45 moles / (1.45 moles + 53.42 moles) = 0.0264 

5 0
3 years ago
What is the molecular formula for a compound that is 44.87% potassium, 36.7%
Phoenix [80]

Answer:

Molecular formula: S4K8O16  empirical formula: SK2O4

Explanation:

First we find the moles of each by first finding grams (using the percent) and then using stoichiometry to convert into moles:

Sulfur: 696 *.18 = 125.28grams S* \frac{1 mole S}{32.065 g S} = 3.907 moles S

Potassium: 696 *.4487 = 312.2952 *\frac{1 mole K}{39.08 g K}= 7.99117 mole K

Oxygen: 696 * .367 = 255.432 * \frac{1 mol O}{16g O} = 15.9654 mole O

Then we divide each value by the atom with the smallest number of moles to find the mole ratio:

3.907/3.907= 1

7.99117 mole K/ 3.907= 2.043

15.9654 mole O/ 3.907= 4.08

The empirical formula is SK2O4

To find the molecular formula, we divide the mass given (696) by the mass of the empirical formula (174.22) to get 4. We then divide each atom by 4.

Molecular formula: S4K8O16

5 0
2 years ago
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