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ruslelena [56]
2 years ago
7

Multiple binomials by polynomials problem (2+3w)(w^2+6w+9)

Mathematics
1 answer:
muminat2 years ago
5 0

Answer:

3w³ + 20w² + 39w + 18

Step-by-step explanation:

It is given that,

(2 + 3w)(w² + 6w + 9)

<u>To find the multiplication</u>

(2 + 3w)(w² + 6w + 9) = 2 * w² + 2 * 6w + 2* 9 + 3w * w² +3w * 6w + 3w* 9

 = 2w² + 12w + 18 + 3w³ + 18w²  + 27w

 = 3w³ + 20w² + 39w + 18

Therefore the final value =  3w³ + 20w² + 39w + 18

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  1. Raising a power to a power: (x^m)^n=x^{m*n}
  2. Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  3. Converting negative exponents to positive ones: x^{-m}=\frac{1}{x^m}\ \textsf{and}\ \frac{1}{x^{-m}}=x^m

Firstly, solve the outer exponent:

(\frac{4mn}{m^{-2}n^{6}})^{-2}=\frac{4^{-2}m^{-2}n^{-2}}{m^{-2*-2}n^{6*-2}}=\frac{4^{-2}m^{-2}n^{-2}}{m^4n^{-12}}

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<u>Your final answer is n^10/16m^6 , or B.</u>

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