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ruslelena [56]
3 years ago
7

Multiple binomials by polynomials problem (2+3w)(w^2+6w+9)

Mathematics
1 answer:
muminat3 years ago
5 0

Answer:

3w³ + 20w² + 39w + 18

Step-by-step explanation:

It is given that,

(2 + 3w)(w² + 6w + 9)

<u>To find the multiplication</u>

(2 + 3w)(w² + 6w + 9) = 2 * w² + 2 * 6w + 2* 9 + 3w * w² +3w * 6w + 3w* 9

 = 2w² + 12w + 18 + 3w³ + 18w²  + 27w

 = 3w³ + 20w² + 39w + 18

Therefore the final value =  3w³ + 20w² + 39w + 18

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An airliner maintaining a constant elevation of 2 miles passes over an airport at noon traveling 500 mi/hr due west. At 1:00 PM,
butalik [34]

Answer:

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

Step-by-step explanation:

Let suppose that airliners travel at constant speed. The equations for travelled distance of each airplane with respect to origin are respectively:

First airplane

r_{A} = 500\,\frac{mi}{h}\cdot t\\r_{B} = 550\,\frac{mi}{h}\cdot t

Where t is the time measured in hours.

Since north and west are perpendicular to each other, the staight distance between airliners can modelled by means of the Pythagorean Theorem:

s=\sqrt{r_{A}^{2}+r_{B}^{2}}

Rate of change of such distance can be found by the deriving the expression in terms of time:

\frac{ds}{dt}=\frac{r_{A}\cdot \frac{dr_{A}}{dt}+r_{B}\cdot \frac{dr_{B}}{dt}}{\sqrt{r_{A}^{2}+r_{B}^{2}} }

Where \frac{dr_{A}}{dt} = 500\,\frac{mi}{h} and \frac{dr_{B}}{dt} = 550\,\frac{mi}{h}, respectively. Distances of each airliner at 2:30 PM are:

r_{A}= (500\,\frac{mi}{h})\cdot (1.5\,h)\\r_{A} = 750\,mi

r_{B}=(550\,\frac{mi}{h} )\cdot (1.5\,h)\\r_{B} = 825\,mi

The rate of change is:

\frac{ds}{dt}=\frac{(750\,mi)\cdot (500\,\frac{mi}{h} )+(825\,mi)\cdot(550\,\frac{mi}{h})}{\sqrt{(750\,mi)^{2}+(825\,mi)^{2}} }

\frac{ds}{dt}\approx 743.303\,\frac{mi}{h}

6 0
3 years ago
Without multiplying determine the sign of the product (-468,256)(183,758).​
maxonik [38]

Answer:

negative

Step-by-step explanation:

rules:

+ + = +

- - = +

+ - = -

- + = -    ----> (-468,256)(183,758)

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The answer would be:


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Standard form of -2x^2+8x+5
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-2x^2+8x+5 is the standard form
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