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3 years ago

Multiple binomials by polynomials problem (2+3w)(w^2+6w+9)

Mathematics

1 answer:

muminat3 years ago

5 0

Answer:

3w³ + 20w² + 39w + 18

Step-by-step explanation:

It is given that,

(2 + 3w)(w² + 6w + 9)

To find the multiplication

(2 + 3w)(w² + 6w + 9) = 2 * w² + 2 * 6w + 2* 9 + 3w * w² +3w * 6w + 3w* 9

= 2w² + 12w + 18 + 3w³ + 18w² + 27w

= 3w³ + 20w² + 39w + 18

Therefore the final value = 3w³ + 20w² + 39w + 18

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