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raketka [301]
3 years ago
7

In the above figure, what's the length of the tangent from the external point D to point B?

Mathematics
2 answers:
choli [55]3 years ago
4 0

It looks like the answer is D) 4.

From C to D is 2, from B to C is 2.

2 + 2 = 4

So, 4 is the answer.

Ira Lisetskai [31]3 years ago
4 0
Answer is 4.

These questions are too easy @lawrencemadisopdp8ld.
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Please help !!<br> Solve for x:<br><br> -2<br> -2/3<br> -3/2<br> -3
Kryger [21]

Answer:

x = \frac{3}{2}

Step-by-step explanation:

Given 2 intersecting chords, then the product of the parts of one chord is equal to the product of the parts of the other chord, that is

18x = 9 × 3 = 27 ( divide both sides by 18 )

x = \frac{27}{18} = \frac{3}{2}

8 0
3 years ago
Omar is making pizzas for his whole family. so far, he has made 5.04 pounds worth of pizzas and has 7 people to feed. how much p
makvit [3.9K]
They'll all get 0.72 pounds
5.04 ÷ 7 = 0.72
7 0
3 years ago
Is 3 pounds greater than less than or = to 50 ounces
elena-s [515]
Three pounds is less than 50 ounces. 3 pounds =48 ounces
8 0
3 years ago
If h(x)=(fog)(x) and h(x)=³√x+3, find g(x) if f(x) =³√x+2
ipn [44]

Answer:

g(x)=x+1

The problem:

Find g(x) if h(x)=(f \circ g)(x),

h(x)=\sqrt[3]{x+3}, and

f(x)=\sqrt[3]{x+2}.

Step-by-step explanation:

h(x)=(f \circ g)(x)

h(x)=f(g(x))

Replace x in f(x)=\sqrt[3]{x+2} with g(x) since we are asked to find f(g(x)):

\sqrt[3]{x+3}=\sqrt[3]{g(x)+2}

\sqrt[3]{x+1+2}=\sqrt[3]{g(x)+2}

This implies that x+1=g(x)

Let's check:

(f \circ g)(x)

f(g(x))

f(x+1)

\sqrt[3]{(x+1)+2}

\sqrt[3]{x+1+2}

\sqrt[3]{x+3}  which is the required result for h(x).

6 0
3 years ago
Which would give the best estimate of 4 and 7/8 times 3 and 6/7
balandron [24]
Me I would go with 3 time 6/7
5 0
3 years ago
Read 2 more answers
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