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3 years ago

How many lines of symmetry does the letter S have?

1 answer:

8 0

The letter S in the alphabet does not have any lines of symmetry. Therefore, the answer to this question is: Zero (0). This is because letter S is not symmetrical when it is cut or divided into 2 parts.

You might be interested in

Two numbers such that the greater number is 75 percent more than the lesser number

victus00 [196]

<h2>Greetings!</h2>

If x = the first number (equal to 1x) then the second number is 75% more than this.

This means the value of the bigger number is 100 + 75 (because 100 is the starting number and 75 is the percent bigger)

This can be shown with the following equation:

Amount * $\frac{percentage}{100}$

x * $\frac{175}{100}$ = 1.75x

1.75x is the value of the bigger number.

<h2>Hope this helps!</h2>

8 0

3 years ago

Plz someone explain it

Savatey [412]

Answer:

-4(8)=x^2-9x+12

-32=x^2-9x+12

Step-by-step explanation: is this what u want us to do?

8 0

2 years ago

Find Z.............

Arada [10]

Answer:

x = 40 degrees

Step-by-step explanation:

We are given that AB and CD are parallel to each other and they are cut by a transversal.

The angle 40 is complementary to angle z, so this means that they have the same measure by the complementary angles theorem.

Complementary are angles that occupy the same space on one parallel line compared to the other parallel line.

Angle z = 40 degrees

5 0

3 years ago

Suppose △PKN≅△BGH△PKN≅△BGH. Which other congruency statements are correct? Select each correct answer. △NKP≅△HBG△NKP≅△HBG △KPN≅△

NeTakaya

Answer:

△NPK≅△HBG; and △KNP≅△GHB

Explanation:

Using the given congruence statement, we can determine corresponding pieces of the triangles:

P corresponds to B; K corresponds to G; and N corresponds to H.

This means that △NKP≅△HGB, not HBG.

△KPN≅△GBH, not BHG.

△NPK≅△HBG; this is correct.

△KNP≅△GHB; this is correct.

8 0

3 years ago

What is the equation of a parabola with a directrix of y=2 and a focus point of 0,-2

KiRa [710]

Hope this helped. :)

Any point, (x0,y0)(x0,y0) on the parabola satisfies the definition of parabola, so there are two distances to calculate:

Distance between the point on the parabola to the focusDistance between the point on the parabola to the directrix

To find the equation of the parabola, equate these two expressions and solve for y0y0 .

Find the equation of the parabola in the example above.

Distance between the point (x0,y0)(x0,y0) and (a,b)(a,b) :

(x0−a)2+(y0−b)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√(x0−a)2+(y0−b)2

Distance between point (x0,y0)(x0,y0) and the line y=cy=c :

∣∣y0−c∣∣| y0−c |

(Here, the distance between the point and horizontal line is difference of their yy -coordinates.)

Equate the two expressions.

(x0−a)2+(y0−b)2‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾‾√=∣∣y0−c∣∣(x0−a)2+(y0−b)2=| y0−c |

Square both sides.

(x0−a)2+(y0−b)2=(y0−c)2(x0−a)2+(y0−b)2=(y0−c)2

Expand the expression in y0y0 on both sides and simplify.

(x0−a)2+b2−c2=2(b−c)y0(x0−a)2+b2−c2=2(b−c)y0

This equation in (x0,y0)(x0,y0) is true for all other values on the parabola and hence we can rewrite with (x,y)(x,y) .

Therefore, the equation of the parabola with focus (a,b)(a,b) and directrix y=cy=c is

(x−a)2+b2−c2=2(b−c)y

3 0

3 years ago