Answer:
P(2.50 < Xbar < 2.66) = 0.046
Step-by-step explanation:
We are given that Population Mean,  = 2.58 and Standard deviation,
 = 2.58 and Standard deviation,  = 0.75
 = 0.75
Also, a random sample (n) of 110 households is taken.
Let Xbar = sample mean household size
The z score probability distribution for sample mean is give by;
              Z =  ~ N(0,1)
 ~ N(0,1)
So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)
P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar  2.50)
 2.50)
P(Xbar < 2.66) = P(  <
 <  ) = P(Z < -1.68) = 1 - P(Z  1.68)
 ) = P(Z < -1.68) = 1 - P(Z  1.68)
                                                               = 1 - 0.95352 = 0.04648
P(Xbar  2.50) = P(
 2.50) = P(  
  
  ) = P(Z
  ) = P(Z  -3.92) = 1 - P(Z < 3.92)
  -3.92) = 1 - P(Z < 3.92)
                                                               = 1 - 0.99996 = 0.00004  
Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046
 
        
             
        
        
        
Answer:
 B.
Step-by-step explanation:
You have to find the total of tickets which is 85 and find the non-winning tickets which is 63. So, the answer is 63:85.
 
        
             
        
        
        
Answer:
pls attach the question.....