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3 years ago

Math challenging and now math challenging me to challenge math

Mathematics

1 answer:

erastovalidia [21]3 years ago

3 0

Answer:

$30

Step-by-step explanation:

Total amount paid by the hire purchase scheme:

$60 + 6 * $45 = $60 + $270 = $330

Total amount paid in just the cash price:

$300

Difference:

$330 - $300 = $30

You might be interested in

Factor 42v^3 – 21v^2 + 34v – 17

BartSMP [9]

Answer:

(2v-1)(21v^2+17)

Step-by-step explanation:

add and subtract the second term to the expression and factor by "grouping"

answer should be:

(2v-1)(21v^2+17)

4 0

3 years ago

I need the answers to #1,#2 and #3

Ede4ka [16]

The answers are #1 45 #2 24 #3 10

6 0

3 years ago

Solve the equation x^2-4x+85=0

lara [203]

Can't factor
use quadratic
for
ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
1x^2-4x+85=0
a=1
b=-4
c=85

x= $\frac{-(-4)+/- \sqrt{(-4)^2-4(1)(85)} }{2(1)}$
x= $\frac{4+/- \sqrt{16-340} }{2}$
x= $\frac{4+/- \sqrt{-324} }{2}$
x= $\frac{4+/- (\sqrt{-1})(\sqrt{324}) }{2}$
remember that √-1=i
x= $\frac{4+/- i(\sqrt{324}) }{2}$
x= $\frac{4+/- i(18) }{2}$
x=2+/-9i

x=2+9i or x=2-9i

3 0

3 years ago

the formula y-y1 =m(x-x1) is the pot slope form of the equation of a line where m is the slope of the line and(x,y) and (x1,y1)

oksano4ka [1.4K]

$\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~{{ 4}} &,&{{ -2}}~) 
% (c,d)
&&(~{{ 5}} &,&{{ 0}}~)
\end{array}
\\\\\\
% slope = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{5-(-2)}{0-4}\implies \cfrac{5+2}{0-4}\implies -\cfrac{7}{4}$

$\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=-\cfrac{7}{4}(x-4)
\\\\\\
y+2=-\cfrac{7}{4}(x-4)\implies y+2=-\cfrac{7}{4}x+7\implies y=-\cfrac{7}{4}x+9$

6 0

3 years ago

Suppose that you draw two cards from a deck. After drawing the first card, you do not put the first card back in the deck. What

AVprozaik [17]

Answer:

The correct answer is 0.05882.

Step-by-step explanation:

A deck of cards have 52 cards, 13 cards of each suit.

We are drawing two cards without replacement.

We need to find the probability of getting a diamond as the first card.

Favorable outcomes are 13 and total number of outcomes are 52.

Thus this probability is $\frac{13}{52} = \frac{1}{4}$ .