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3 years ago

HELP ME SOLVE THIS DUE TOMORROW!!

Mathematics

1 answer:

Sedaia [141]3 years ago

8 0

Answer mine and I will answer yours

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Find f(x) of -n^2 -3n if x is -5

dangina [55]

Answer:

-40

Step-by-step explanation:

f(5)= -(5)^2-3(5)

-25-15=-40

5 0

3 years ago

Joshua started cycling at 5:15 pm By 8:09 pm, he has covered a distance of 7250 mWhat was Joshua's average speed during that tim

vivado [14]

The average speed of Joshua during that time is 2500 m/h.

Explanation:

It is given that Joshua started cycling at 5:15 pm. By 8:09 pm he has covered a distance of 7250 m.

The total time taken by Joshua from 5:15 pm to 8:09 pm is

$2 { h } 54 \text { min }=2 \mathrm{h}+\frac{54}{60} {h}$

Dividing we get,

$2 { h } 54 \text { min }=2 \mathrm{h}+0.9 {h}$

Adding, we have,

$2 { h } 54 \text { min }=2.9 {h}$

Thus, the total time taken by Joshua is $2.9 {h}$

To determine the average speed we use the formula,

$speed=\frac{distance}{time}$

where $distance=7250$ and $time=2.9$

Hence, substituting the values we have,

$speed=\frac{7250}{2.9}$

Dividing, we get,

$speed=2500$

Thus, the average speed of Joshua during that time is 2500 m/h.

5 0

3 years ago

Unit 1: Scientific Notation Constructed Response Assignment

balu736 [363]

brainly.com/question/5027087

Let C, S and H be the diameters of cell, sand and hair

Diameter of a cell: $C=1 \cdot 10^{-5}m$

Diameter of a grain of sand: $S=2 \cdot10^{-4}m$

Part A:

$H=0.000025=2.5 \cdot 10^{-5}$ meters, because it takes 5 movements right of the decimal dot, until there is only one digit to its left.

Part B:

we are comparing $S=2 \cdot10^{-4} m$ to $C=1 \cdot10^{-5} m$ ,

$\frac{S}{C}= \frac{2 \cdot 10^{-4}}{1 \cdot 10^{-5}}=\frac{20 \cdot 10^{-5}}{1 \cdot 10^{-5}}=20$

thus S is 20 times larger than C

Part C

$1m=1 \cdot10^9nm$

thus,

$H=2.5 \cdot 10^{-5}m=2.5 \cdot 10^{-5} \cdot 1 \cdot 10^9nm=2.5 \cdot 10^{-5+9}=2.5\cdot10^4nm$

Part D.

$1m=1\cdot 10^9nm\\\\1nm=\displaystyle{ \frac{1m}{10^9}=1\cdot 10^{-9}m}$

thus 300 nm are written in meters as follows:

$300nm= 300\cdot 1\cdot 10^{-9}m=3\cdot 10^2 \cdot 10^{-9}m=3\cdot 10^{-7}m$

5 0

3 years ago

The area of rectangular field is (49m2-42m+9).Find the dimensions of the field

Drupady [299]

Answer:

The dimensions are (7m-3) by (7m-3)

Step-by-step explanation:

We have the area of the rectangular field to be:

$49 {m}^{2} - 42m + 9$