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3 years ago

Please help me with this!

Mathematics

2 answers:

Igoryamba3 years ago

7 0

Answer:

1: 39,284

2: 58,672.8

3: 2,066.79153912

4: 183.801664976

5: 8,744,119.16410

Those are the answers to the problems now you can just determine which ones are from least to greatest

Taya2010 [7]3 years ago

4 0

Answer:

1: 39,284

2: 58,672.8

3: 2,066.79153912

4: 183.801664976

5: 8,744,119.16410

Step-by-step explanation:

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Solve for x: -3 + x = -22

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Answer:

x= -19

Step-by-step explanation:

-3 + x = -22

Add 3 to each side

-3+3 +x = -22 +3

x = -19

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4 years ago

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Please hurry. Solve the equation

Lelu [443]

The value of x is $5\sqrt[3]{25}$ .

Solution:

Given expression is $-7=8-3 \sqrt[5]{x^{3}}$ .

Switch both sides.

$8-3 \sqrt[5]{x^{3}}=-7$

Subtract 8 from both side of the equation.

$8-3 \sqrt[5]{x^{3}}-8=-7-8$

$-3 \sqrt[5]{x^{3}}=-15$

Divide by –3 on both side of the equation.

$$\frac{-3 \sqrt[5]{x^{3}}}{-3} =\frac{-15}{-3}$

$\sqrt[5]{x^{3}}=-5$

To cancel the cube root, raise the power 5 on both sides.

$(\sqrt[5]{x^{3}})^5=(-5)^5$

$x^3=3125$

To find the value of x, take square root on both sides.

$\sqrt[3]{x^3}=\sqrt[3]{25}$

$x=5\sqrt[3]{25}$

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3 years ago

Solve each equation with the quadratic formula. (Show work please)

Snowcat [4.5K]

Answer:

Let b=x

Such that b^2 =8b-8 will x^2=8x-8

Using the almighty quadratic formula

x1={-b+sqrt (b^2-4ac)}/2a

x2={-b-sqrt (b^2-4ac)}/2a

From the question

a=1

b=8

c=-8

x1={-8+sqrt (8^2-4(-8))}/2

x1=(-8+5.66)/2

x1=-1.17

x2={-8-sqrt (8^2-4(-8))}/2

x2=(-8-5.66)/2

x2=-6.83

:.(x1,x2)=(-1.17,-6.83)

Step-by-step explanation:

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3 years ago