Prove that there exists a unique real number solution to the equation x3 + x2 − 1 = 0 between x = 2/3 and x=1
1 answer:
You might be interested in
Answer:
D
Step-by-step explanation:
To evaluate the value of the function at 3, draw vertical line and find the point of intersection of this line with the graph of the given function.
You can see that the vertical line has two common points with the graph: (3,5) and (3,7). The first point (3,5) is solid (filled), so this point belongs to the graph and it is the point of intersection. The second point (3,7) is open point (not filled), so this point does not belong to the graph, so it cannot be the point of intersection.
Hence,
Answer:
1.39
Step-by-step explanation:
According to the problem, calculation of the given data are as follows,
Given equation = 0=2x2+3x-8
Here, we use general formula of quadratic equation, then
By taking the value by given equation,
a = 2, b = 3, c= -8
by putting the value in equation , we get
x = [- 3 ± √3^2 - 4(2 × -8)] ÷ 2×2
= [- 3 ± √73] ÷ 4
= [- 3 ± 8.544] ÷ 4
So, for positive solution, we get
x = (-3 + 8.544) ÷ 4
x = 1.386 or 1.39