Prove that there exists a unique real number solution to the equation x3 + x2 − 1 = 0 between x = 2/3 and x=1
1 answer:
Replace each of the x values given to see if they give 0.
0=(2/3)³+(2/3)²-1
0=(8/27)+(4/9)-1
0≠-0.259
0=(1)³+(1)²-1
0≠1
Therefore, you can see that the solution would have to be between 2/3 and 1.
Hope I helped :)
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