<span>The number of cell phone minutes used by high school seniors follows a normal distribution with a mean of 500 and a standard deviation of 50. what is the probability that a student uses more than 580 minutes?
Given
μ=500
σ=50
X=580
P(x<X)=Z((580-500)/50)=Z(1.6)=0.9452
=>
P(x>X)=1-P(x<X)=1-0.9452=0.0548=5.48%
</span>
Answer: 
Step-by-step explanation:
I Believe the mean would would 60 degrees Fahrenheit
Berto can purchase
12/3.75 gallons, this is 3.2 gallons of gas. So the coordinate on
this line would be (3.2, 12).
Good Luck! :D
You will see a tiny picture up top of the question and draw it out and added then work
