Answer:
-4x^4-6x^3-8x^2-24x
Step-by-step explanation:
![\left(2x^2+4x\right)\left(-2x^2+x-6\right)\\](https://tex.z-dn.net/?f=%5Cleft%282x%5E2%2B4x%5Cright%29%5Cleft%28-2x%5E2%2Bx-6%5Cright%29%5C%5C)
distribuir parênteses
![=2x^2\left(-2x^2\right)+2x^2x+2x^2\left(-6\right)+4x\left(-2x^2\right)+4xx+4x\left(-6\right)](https://tex.z-dn.net/?f=%3D2x%5E2%5Cleft%28-2x%5E2%5Cright%29%2B2x%5E2x%2B2x%5E2%5Cleft%28-6%5Cright%29%2B4x%5Cleft%28-2x%5E2%5Cright%29%2B4xx%2B4x%5Cleft%28-6%5Cright%29)
Aplicar regras de menos mais ;![+\left(-a\right)=-a](https://tex.z-dn.net/?f=%2B%5Cleft%28-a%5Cright%29%3D-a)
![=-2\times\:2x^2x^2+2x^2x-2\times\:6x^2-4\times\:2x^2x+4xx-4\times\:6x](https://tex.z-dn.net/?f=%3D-2%5Ctimes%5C%3A2x%5E2x%5E2%2B2x%5E2x-2%5Ctimes%5C%3A6x%5E2-4%5Ctimes%5C%3A2x%5E2x%2B4xx-4%5Ctimes%5C%3A6x)
simplificar
![-2\times\:2x^2x^2+2x^2x-2\times\:6x^2-4\times\:2x^2x+4xx-4\times\:6x:\\\quad -4x^4-6x^3-8x^2-24x](https://tex.z-dn.net/?f=-2%5Ctimes%5C%3A2x%5E2x%5E2%2B2x%5E2x-2%5Ctimes%5C%3A6x%5E2-4%5Ctimes%5C%3A2x%5E2x%2B4xx-4%5Ctimes%5C%3A6x%3A%5C%5C%5Cquad%20-4x%5E4-6x%5E3-8x%5E2-24x)
The answer is: "3" .
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Use the Pythagorean theorem (for right triangles):
a² + b² = c² ;
in which "a = "side length 1" (unknown; for which we which to solve);
"b" = "side length 2" = "√3" (given in the figure) ;
"c" = "length of hypotenuse" = "2√3" (given in the figure);
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a² + b² = c² ;
a² = c² − b² ;
Plug in the known values for "c" and "b" ;
a² = (2√3)² − (√3)² ;
Simplify:
(2√3)² = 2² * (√3)² = 2 * 2 * (√3√3) = 4 * 3 = 12 .
(√3)² = (√3√3) = 3 .
a² = 12 − 3 = 9 .
a² = 9
Take the "positive square root" of EACH SIDE of the equation; to isolate "a" on one side of the equation; & to solve for "a" ;
+√(a²) = +√9 ;
a = 3 .
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The answer is: "3" .
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Answer: x=158
Explain: 3 triangle corners = 180
180-90-68 = 22
Flat corner = 180
=> x=180-22=158
-2x^2(4x − 3)
=-8x^3 + 6x^2
hope it helps
Answer:
they are already correct first true second true third false and 4th true
Step-by-step explanation:
np brainliest?