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MatroZZZ [7]
3 years ago
11

g A pharmaceutical manufacturer has been researching new formula to provide quicker relief of minor pains. His laboratories have

produced several different formula which he wanted to test. Fifteen people who complained of minor pains were recruited for an experiment. Five were given formula 1, five were given formula 2, and the last five were given formula 3. Each was asked to take the medicine and report (X) the length of time until some relief was felt. Using the results of the output, at 0.05 level of significance, what is the critical value for testing differences in the population mean times for pain relief
Mathematics
1 answer:
evablogger [386]3 years ago
6 0

Answer:

Step-by-step explanation:

From the question we are told that

   The sample size is  n =  15

   The  level of significance is  \alpha =  0.05

The null hypothesis is  H_o:\mu_1 = \mu_2 = \mu_3

The alternative hypothesis is H_a : \mu_1 \ne \mu_2 \ne \mu_3

Generally the degree of freedom is mathematically represented  as

       df  =  5 +  5 +  5  - 3

=>     df  =  12

Generally the critical value of \alpha =  0.05 at a degree of freedom of df  =  12 is

        t_{0.05 , 12} = \pm 2.1788

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