find the values of x between 0 and 2pi where the tangent line to the graph of y=sinxcosx is horizontal.
1 answer:
<span>y = sin x + cos x the tangent will be horizontal when the derivative is 0 y ' = cos x - sin x 0 = cos x - sin x sin x = cos x tan x = 1 this happens when x = pi/4 or 5pi/4 y(pi/4) = sqrt(2) / 2 + sqrt(2) / 2 = sqrt(2) y(5pi/4) = -sqrt(2) / 2 + -sqrt(2) / 2 = -sqrt(2) the two points are: (pi/4 , srqt(2)) and (5pi/4 , -srqt(2)) I hope my answer has come to your help. Thank you for posting your question here in Brainly. </span>
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