find the values of x between 0 and 2pi where the tangent line to the graph of y=sinxcosx is horizontal.
1 answer:
<span>y = sin x + cos x
the tangent will be horizontal when the derivative is 0
y ' = cos x - sin x
0 = cos x - sin x
sin x = cos x
tan x = 1
this happens when x = pi/4 or 5pi/4
y(pi/4) = sqrt(2) / 2 + sqrt(2) / 2 = sqrt(2)
y(5pi/4) = -sqrt(2) / 2 + -sqrt(2) / 2 = -sqrt(2)
the two points are: (pi/4 , srqt(2)) and (5pi/4 , -srqt(2))
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Sorry if I'm wrong I'm mr lemonade