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Aloiza [94]
3 years ago
11

If A = 4 what is the value of the expression 12 - a/4

Mathematics
2 answers:
kherson [118]3 years ago
8 0
Put 4 where "a" is and do the arithmetic.
12-\dfrac{a}{4}=12-\dfrac{4}{4}=12-1=11

The value of the expression is 11.


_____
This is very different from
\dfrac{12-a}{4}=\dfrac{12-4}{4}=\dfrac{8}{4}=2
In this latter case, parentheses are required when the expression is rendered using plain text: (12 -a)/4.
antiseptic1488 [7]3 years ago
7 0
I hope this helps!!

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-12 n - 24 = -12 (n+2) 

-12 (n+2)  is the answer
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4 0
3 years ago
If you can explain your answer that’d be great!! Thank you!
Rasek [7]

Answer:

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

A(t)=A_{0}e^{kt}

Where

k=\frac{ln(\frac{1}{2})}{Half-Life}

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}

Now

A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}

third choice is correct.

8 0
3 years ago
Solve the following system.
PSYCHO15rus [73]

<em><u>answers</u></em>

y=2×2+3×-1 and x+ y= -1

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y =2×2+3x-1and x + y =1y= -2×2+3x-7 and x+y=-2x3x-1and x+y =-1

6 0
3 years ago
Me pueden ayudar en esta ecuación bicuadratica, porfaaa: 9p⁴=—12x²—6/9
Dominik [7]

Answer:

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Step-by-step explanation:

Pregunta correcta

¿Me pueden ayudar en esta ecuación biquadratica, por favor: 9x⁴ = —12x² - 6/9

Solución

9x⁴ = —12x² - 6/9

9x⁴ + 12x² + 6/9 = 0

multiplicar por 9

81x⁴ + 108x² + 6 = 0

Deje x² = y, entonces x⁴ = y²

81y² + 108y + 6 = 0

Resolviendo esta ecuación cuadrática

y = -0.0581 o y = -1.275

Recordemos, x² = y

x = ±√y

Si y = -0.0581

x = ± √(-0.0581) = ± 0.241i = 0.241i o -0.241i

Si y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i o -1.129i

x = -1.129i, -0.241i, 0.241i o 1.129i.

Tenga en cuenta que i = √(-1), i es el representante de un número complejo.

¡¡¡Espero que esto ayude!!!

Correct Question

Can you help me in this biquadratic equation, please: 9x⁴ = —12x² — 6/9

Solution

9x⁴ = —12x² — 6/9

9x⁴ + 12x² + 6/9 = 0

multiply through by 9

81x⁴ + 108x² + 6 = 0

Let x² = y, then x⁴ = y²

81y² + 108y + 6 = 0

Solving this quadratic equation

y = -0.0581 or y = -1.275

Recall, x² = y

x = ±√y

If y = 0.0581

x = ±√(-0.0581) = ±0.241

If y = -1.275

x = ± √(-1.275) = ± 1.129i = 1.129i or -1.129i

Hence x = -1.129i, -0.241i, 0.241i or 1.129i.

Note that i = √(-1), i is the representative of a complex number.

Hope this Helps!!

5 0
3 years ago
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