Answer:
*See below*
Step-by-step explanation:
<u>Identify and Explain Error</u>
The method shown is using fractions to compare costs. This strategy does not work due to the fact that they have not factored in the $55 he pays for the car before hand. Also, 150 divided by 0.5 does not equal 30, it equals 300 so, even if he did not pay $55 beforehand, the equation is still incorrect.
<u>Correct Work/Solution</u>
$55 to rent
$0.50 per mile
Let's start by removing $55 from $150 to see how many dollars is left over for gas.
150 - 55 = 95
Then, divide 95 by 0.5
95 ÷ 0.5 = 190
He can drive at least 190 miles.
<u>Share Strategy</u>
Since he starts off paying $55 dollars out of $150, we need to subtract $55 by $150 to see how much cash he has left over for mileage. $150 minus $55 equals $95 so, he has $95 left over for mileage. $95 will then be divided by $0.50 to find out how many miles he can drive. We are dividing by $0.50 because that's the cost per mile. $95 divided by $0.50 equals 190 so he can drive at least 190 miles.
Note:
Hope this helps :)
Have a great day!
Answer:
Step-by-step explanation:
To find : Acceleration in first 15 min . Distance between two cities Average speed of journey
Solution:
Each horizontal block is 1/8 hr = 7.5 min
Each vertical block is 10 km/hr
Time Velocity km/hr
0 Min ( 0 hr) 0
15 Min (1/4 hr) 50
45 Min (3/4 hr) 50
60 MIn ( 1 hr) 100
90 Min ( 3/2 hr) 100
120 Min ( 2hr) 0
Acceleration in first 15 min (1/4 hr) = (50 - 0)/(1/4 - 0) = 50/(1/4)
= 200 km/h²
Distance between two cities
= (1/2)(0 + 50)(1/4 - 0) + 50 * (3/4 - 1/4) + (1/2)(50 + 100)(1 - 3/4) + 100 * (3/2 - 1) + (1/2)(100 + 0)(2 - 3/2)
= 25/4 + 25 + 75/4 + 50 + 25
= 125
Distance between two cities = 125 km
Average Speed of journey = 125/2 = 62.5 km/hr
Acceleration in first 15 min = 200 km/h²
Distance between two cities = 125 km
Average Speed of journey = 62.5 km/hr
Hope this helps..
350 mm shared in this ratio
Answer:
A = 413 sq feet
Step-by-step explanation:
The area of the yard = area of rectangle - area of semicircle
The radius of the semicircle, r = 10 feet
The length of the rectangle = 38.5 - 10 = 28.5 feet
So,
The area of the yard = lb - (πr²/2)
So, the required area is equal to 413 sq feet.
