You can revise: the sum of the two adjacent angles is 180°
and the sum of the measurements of the three corners in a triangle is also 180°
<1= 180°-57°=123°
As <2=52°, so we have <3= 180°-(28°+71°+52°)= 180°-151°=29°
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The ticket price which will maximize the student's council is: C. $3.10.
<h3>What is price?</h3>
Price can be defined as an amount of money which is primarily set by the seller of a product, and it must be paid by a buyer to the seller, so as to enable the acquisition of this product.
Based on the information provided about Valley High School student council, we can logically deduce the following data:
- Total number of students = 420 students.
- Lowest ticket price = $2.00.
- Increase in ticket price = $0.20.
- Attendance = 20 fewer students
<h3>How to determine the ticket price?</h3>
Mathematically, the equation which model the profit is given by:
Profit = price × number of tickets sold
P(x) = (2 + 0.2x)(420 - 20x)
P(x) = 840 + 84x - 40x - 4x²
P(x) = -4x² + 44x + 840.
For any quadratic equation with a parabolic curve, the axis of symmetry is given by:
Xmax = -b/2a
Xmax = -44/2(-4)
Xmax = -44/-8.
Xmax = 5.5
Ticket price for maximum profit is given by:
Ticket price = 2 + 0.2x
Ticket price = 2 + 0.2(5.5)
Ticket price = $3.10.
Read more on maximized profit here: brainly.com/question/13800671
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Answer:
Assuming you have the lengths in inches.
Do this: (length in inches * 10) x (length in inches * 10)
Step-by-step explanation:
There's information missing from this question. "The football field is 100 yards long and yards wide", but to find out the area of a rectangle you just need to times the two numbers together.
I assume you have a picture with the lengths in inches on, if you can see how many inches are on the scale drawing, times the inches by 10 for the length in yards for each side. Then times the two lengths (in yards) together for the area.
:)
Answer:
Step-by-step explanation:
h(x)=12/x
h(a)= 12/a ( a is a variable number just replace x with a)
The sum of all the even integers between 99 and 301 is 20200
To find the sum of even integers between 99 and 301, we will use the arithmetic progressions(AP). The even numbers can be considered as an AP with common difference 2.
In this case, the first even integer will be 100 and the last even integer will be 300.
nth term of the AP = first term + (n-1) x common difference
⇒ 300 = 100 + (n-1) x 2
Therefore, n = (200 + 2 )/2 = 101
That is, there are 101 even integers between 99 and 301.
Sum of the 'n' terms in an AP = n/2 ( first term + last term)
= 101/2 (300+100)
= 20200
Thus sum of all the even integers between 99 and 301 = 20200
Learn more about arithmetic progressions at brainly.com/question/24592110
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