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Readme [11.4K]
4 years ago
13

Write the complete electron configuration of germanium, element 32

Chemistry
1 answer:
Ghella [55]4 years ago
6 0

1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p2, valence shell: 4s2 3d10 4p2

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What mass of znco3 contains 6.11×1022 o atoms? give your answer correctly to three significant digits?
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Using Avogadros number, we can get that 1 mole of an atom contain 6.022 x 10^23 atoms. Therefore we can use this conversion factor to get the number of moles:

moles ZnCO3 = 6.11 x 10^22 atoms * (1 mole / 6.022 x 10^23 atoms) = 0.10146 moles

 

The molar mass of ZnCO3 is about 125.39 g/mol, therefore the mass is:

mass ZnCO3 = 0.10146 moles * (125.39 g / mol)

<span>mass ZnCO3 = 12.72 g</span>

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