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Oksi-84 [34.3K]
3 years ago
9

If a hazardous bottle is labeled 20.2 % by mass Hydrochloric Acid, HCl, with a density of 1.096 g/mL. Calculate the molarity of

the HCl solution.
a. 6.07 M
b. 0.22 M
c. 14.7 M
Chemistry
1 answer:
Brut [27]3 years ago
8 0

<u>Answer:</u> The molarity of HCl solution is 6.07 M

<u>Explanation:</u>

We are given:

20.2 % hydrochloric acid solution

This means that 20.2 grams of hydrochloric acid is present in 100 grams of solution

To calculate the volume for given density of substance, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

Mass of solution = 100 g

Density of solution = 1.096 mL

Putting values in above equation, we get:

1.096g/mL=\frac{100g}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{100g}{1.096g/mL}=91.24mL

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

Given mass of hydrochloric acid = 20.2 g

Molar mass of hydrochlroic acid = 36.5 g/mol

Volume of solution = 91.24 mL

Putting values in above equation, we get:

\text{Molarity of solution}=\frac{20.2\times 1000}{36.5g/mol\times 91.24}\\\\\text{Molarity of solution}=6.07M

Hence, the molarity of HCl solution is 6.07 M

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Answer:

(CPI) Consumer Price Index

Explanation:

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6 0
3 years ago
In an experiment, 3.25 g of NH3 are allowed to react with 3.50 g of O2. 4NH3 + 5O2 &gt; 4NO + 6H2O a. Which reactant is the limi
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Answer:

2.61 g of NO will be formed

The limiting reagent is the O₂

Explanation:

The reaction is:

4NH₃  +  5O₂  →  4NO  +  6H₂O

We convert the mass of the reactants to moles:

3.25g / 17 g/mol = 0.191 moles of NH₃

3.50g / 32 g/mol =0.109 moles of O₂

Let's determine the limiting reactant by stoichiometry:

4 moles of ammonia react with 5 moles of oxygen

Then, 0.191 moles of ammonia will react with (0.191 . 5) / 4 = 0.238 moles of oxygen. We only have 0.109 moles of O₂ and we need 0.238, so as the oxygen is not enough, this is the limiting reagent

Ratio with NO is 5:4

5 moles of oxygen produce 4 moles of NO

0.109 moles will produce (0.109 . 4)/ 5 = 0.0872 moles of NO

We convert the moles to mass, to get the answer

0.0872 mol . 30g / 1 mol = 2.61 g

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Using the reagents below, list in order (by letter, no period) those necessary to transform 1-chlorobutane into 1-butyne. Note:
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Answer:

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Sodamide (NaNH2) is a very strong base and generally results in Terminal Alkynes when treated with Vicinal Dihalides.

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2NaOH + H2SO4 --&gt; Na2SO4 + 2H2O
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Answer:

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Explanation:

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The graph would not have plummeted if various species were planted due to improvement of the potato crops.

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