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ANEK [815]
1 year ago
6

What is the ph of an aqueous solution with a hydrogen ion concentration of [H+]=1. 2×10^−8 m?

Chemistry
1 answer:
il63 [147K]1 year ago
4 0

The pH of an aqueous solution with a hydrogen ion concentration of [H+]=1. 2×10^−8 m is  7.92.    

The entire form of pH is potential of Hydrogen. pH is called the poor logarithm of H+ ion attention. hence the that means of the name pH is explained because the energy of hydrogen. pH describes the concentration of the hydrogen ions in a solution and it's miles the indicator of acidity or basicity.

pH is an important amount that reflects the chemical conditions of an answer. The pH can manage the provision of vitamins, organic features, microbial activity, and the conduct of chemical substances.

pH stands for capacity hydrogen and it's used to explain the acidity or alkalinity of a substance. The pH scale is measured from 1 to fourteen. 7 is impartial and the lower the quantity, the extra acidic and the higher, the greater alkaline.

explaination,

[H+]=1. 2×10^−8 m

log[h+] = 1. 2×10^−8 m

        =   8 - log (1.2)

        =   8 - 0.079

PH  = 7.921    

Learn more about pH here:-brainly.com/question/172153

#SPJ4

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238,2U --&gt; 234Th +<br> 90
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Answer:

\\_{2}^{4} \alpha

Explanation:

In this question, we wish to find the missing nuclei for the equation:

\\_{92}^{238} U\rightarrow _{90}^{234} Th + _{Z}^{A} X

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238 = 234 + A

Notice from here that:

A = 238 - 234 = 4

So far we know that the mass of X is 4. Similarly, we apply the law of charge conservation. The total charge should be conserved:

92=90+Z

From here:

Z = 92-90=2

We have a particle:

\\_{2}^{4} X

Looking at the periodic table, an atom with Z = 2 corresponds to helium. This can also be written as an alpha particle:

\\_{2}^{4} \alpha

5 0
3 years ago
A reaction at -6.0 °C evolves 786. mmol of sulfur tetrafluoride gas. Calculate the volume of sulfur tetrafluoride gas that is co
borishaifa [10]

Answer:

V of Sulfur tetrafluoride is  17.2 L

Explanation:

Given data;

T = -6°C =  267K                                [1° C  = 273 K]

n = 786 mmol of SF4 which is 0.786 mol

P = 1 atm

from ideal gas law  we have

PV = nRT

where n is mole, R is gas constant, V is volume

V = \frac{nRT}{P}V = \frac{0.786 mol \times 0.082 atmL/mol K \times* 267K}{1atm} = 17.2 L

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6 0
3 years ago
If the vapor pressure of ethanol at 34.7degree C is 100
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Answer:

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where

P1 and P2 are the vapour pressures at temperatures  T1 and T2

Δ vapH  = the enthalpy of vaporization of the ETHANOL

R  = the Universal Gas Constant

In this problem,

P 1 = 100 mmHg

;  T 1 = 34.7 °C = 307.07 K

P 2 = 760mmHg

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T⁻²=0.002813

T² = 355.47K

6 0
3 years ago
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