This ion has 12 protons,12 neutrons and 10 electrons because the element lost 2 electrons and turned to a positive ion
Answer:
The volume of cupboard is 2.0043 m³.
Explanation:
Given data:
width of cupboard = 1.31 m
length of cupboard = 0.9 m
height of cupboard = 1.70 m
Volume = ?
Solution:
Volume = length × width × height
Volume = 0.9 m × 1.31 m × 1.70 m
Volume = 2.0043 m³
The volume of cupboard is 2.0043 m³.
Answer:
Arsenic Trisulfide
Explanation:
It is an inorganic compound. It is bright yellow and insoluble in water.
Answer:
0.120M is the concentration of the solution
Explanation:
<em>Assuming the mass of sodium nitrate dissolved was 2.552g</em>
<em />
Molar concentration is an unit of concentration widely used in chemsitry defined as the moles of solute (In this case NaNO3) in 1L of solution.
To find this question we must find the moles of NaNO3 in 2.552g. With this mass and the volume (250mL = 0.250L) we can find molar concentration as follows:
<em>Moles NaNO3 -Molar mass: 84.99g/mol-</em>
2.552g * (1mol / 84.99g) = 0.0300 moles NaNO3
<em>Molar concentration:</em>
0.0300 moles NaNO3 / 0.250L =
<h3>0.120M is the concentration of the solution</h3>
Answer:
0.492 J/g °C
General Formulas and Concepts:
<u>Thermodynamics</u>
Specific Heat Formula: q = mcΔT
- <em>q</em> is heat (in J0
- <em>m</em> is mass (in g)
- <em>c</em> is specific heat (in J/g °C)
- <em>ΔT</em> is change in temperature (in °C)
Explanation:
<u>Step 1: Define</u>
<em>Identify variables</em>
[Given] <em>q</em> = 45.0 J
[Given] <em>m</em> = 8.10 g
[Given] <em>ΔT</em> = 24.3 °C - 13.0 °C = 11.3 °C
[Solve] <em>c</em>
<em />
<u>Step 2: Solve for </u><em><u>c</u></em>
- Substitute in variables [Specific Heat Formula]: 45.0 J = (8.10 g)c(11.3 °C)
- Multiply: 45.0 J = (91.53 g °C)c
- Isolate <em>c</em>: 0.491642 J/g °C = c
- Rewrite: c = 0.491642 J/g °C
<u>Step 3: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.491642 J/g °C ≈ 0.492 J/g °C
