Question

Arrange the following aqueous solutions, all at 25 ∘C, in order of decreasing acidity. 1 = most acidic; 4 = least acidic Rank from most acidic to most basic: 0.0018 M OH- 0.023 M H3O+ pH = 9.45 pOH = 5.52

Answer 1

Answer:

1. 0.023 M H3O+.

2. pOH = 5.52.

3. pH=9.45

4. 0.0018 M OH-

Explanation:

Hello,

In this case, such order could be computed by means of the pH, the lower the pH the more acid the solution, thus:

1. 0.0018 M OH-:

$pOH=-log(0.018)=1.744\\pH=14-pOH=12.2$

2. 0.023 M H3O+

$pH=-log(0.023)=1.64$

3. pH=9.45

4.

$pH=14-5.52=8.48$

Therefore the order is

1. 0.023 M H3O+.

2. pOH = 5.52.

3. pH=9.45

4. 0.0018 M OH-

Best regards.