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Blizzard [7]
3 years ago
13

How do we determine the volume of an irreguler shaped object?

Chemistry
1 answer:
kicyunya [14]3 years ago
6 0

Answer:

You can measure the displacement when the object is placed in a certain volume of water.

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What's the Balance equation for:<br>_C4H10O +_ O2---&gt;_CO2+_H20​
steposvetlana [31]

Answer:

C₄H₁₀O + 6O₂ ⇒ 4CO₂ + 5H₂O

Explanation:

Match the amount of reactants and products on both sides of the equation.

3 0
3 years ago
Tonya had a mixture of sand, salt, iron particles, and pebbles. What processes should be used to separate the substances in the
marusya05 [52]

Explanation:

Put the pan into a water-containing dish and mix well. Now use a strainer to transfer the solution into another jar. The salt should disappear in it. 

And using a tube with a filtrate, transfer the salts that has sand into another bottle with a filtrate. Therefore the sand is split. Eventually, when all the water vaporizes and the salt stays in the bottle, leave the extra solvent and heat it.

3 0
3 years ago
A buffer solution contains 0.479 M NaHCO3 and 0.342 M Na2CO3. Determine the pH change when 0.091 mol HNO3 is added to 1.00 L of
pshichka [43]

Answer:

ΔpH = 0.20

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

There are 0.479moles of NaHCO₃ and 0.342moles of Na₂CO₃.

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.342mol / 0.479mol

<em>pH = 10.05</em>

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.091 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.342mol + 0.091mol: 0.433mol

HCO₃⁻: 0.479mol - 0.091 mol: 0.388mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.433mol / 0.388mol

pH = 10.25

That means change of pH, ΔpH is:

ΔpH = 10.25 - 10.05 = <em>0.20</em>

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I hope it helps!

3 0
3 years ago
How did Bohr solve the contradiction with physics with his model of an atom
daser333 [38]

Answer:

He used Velocity and Radius.

Explanation:

The uncertainty truths contradicts Bohr's thoughts of electrons.

4 0
3 years ago
Based on the oxidation states of the atoms in this reaction, answer the questions. Fe(0) + O2(0) → Fe2(3+)O3(2-) How many electr
Oliga [24]
Half reaction 1: 2Fe° → Fe₂³⁺ + 6e⁻ /×2.
4Fe° → 2Fe₂³⁺ + 12e⁻.
Iron is oxidized from neutral charge (0) to oxidation number +3, one iron lose three electrons, two irons lose six electrons and four irons twelve electrons.
Half reaction 2: 12e⁻ + 3O₂ → 2O₃²⁻ 
Oxygen is reduced from neutral chage to oxidation number -2, one oxygen gain two electrons, six oxygens gain twelve electrons.
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.
6 0
3 years ago
Read 2 more answers
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